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Mathematical Methods for Physicists: A concise introduction - Site Map

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APPENDIX 2 DETERMINANTS<br />

Example A2.2<br />

1 3 0<br />

1 3 0<br />

1 1 0<br />

1 1 0<br />

2 6 4<br />

ˆ 2<br />

1 3 2<br />

ˆ 2 3<br />

1 1 2<br />

ˆ 2 3 2<br />

1 1 1<br />

ˆ12:<br />

1 0 2<br />

1 0 2<br />

1 0 2<br />

1 0 1<br />

(3) The value of a determinant is not altered if its rows are written as columns,<br />

in the same order.<br />

Proof: Since the same value is obtained whether we expand a determinant by<br />

any row or any column, thus we have property (3). The following example will<br />

illustrate this property.<br />

Example A2.3<br />

1 0 2<br />

D ˆ<br />

1 1 0<br />

ˆ 1 1 0<br />

1 3 0 1 0<br />

2 3 ‡ 2 1 1<br />

2 1 ˆ 1:<br />

2 1 3<br />

Now interchanging the rows and the columns, then evaluating the value of the<br />

resulting determinant, we ®nd<br />

1 1 2<br />

0 1 1<br />

ˆ 1 1 1<br />

0 3 …1† 0 1<br />

2 3 ‡ 2 0 1<br />

2 0 ˆ 1;<br />

2 0 3<br />

illustrating property (3).<br />

(4) If any two rows (or two columns) of a determinant are interchanged, the<br />

resulting determinant is the negative of the original determinant.<br />

Proof: The proof is by induction. It is easy to see that it holds <strong>for</strong> 2 2 determinants.<br />

Assuming the result holds <strong>for</strong> n n determinants, we shall show that it<br />

also holds <strong>for</strong> …n ‡ 1†…n ‡ 1† determinants, thereby proving by induction that it<br />

holds in general.<br />

Let B be an …n ‡ 1†…n ‡ 1† determinant obtained from D by interchanging<br />

two rows. Expanding B in terms of a row that is not one of those interchanged,<br />

such as the kth row, we have<br />

B ˆ Xn<br />

jˆ1<br />

…1† j‡k b kj M 0 kj;<br />

where M 0 kj is the minor of b kj . Each b kj is identical to the corresponding a kj (the<br />

elements of D). Each M 0 kj is obtained from the corresponding M kj (of a kj )by<br />

544

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