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Mathematical Methods for Physicists: A concise introduction - Site Map

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SPECIAL FUNCTIONS OF MATHEMATICAL PHYSICS<br />

Then expanding coecients of z n in Eq. (7.15) leads to the recurrence relation<br />

…2n ‡ 1†xP n …x† ˆ…n ‡ 1†P n‡1 …x†‡nP n1 …x†:<br />

…7:16†<br />

This gives P 4 ; P 5 ; P 6 , etc. very quickly in terms of P 0 ; P 1 , and P 3 .<br />

Recurrence relations are very useful in simplifying work, helping in proofs<br />

or derivations. We list four more recurrence relations below without proofs or<br />

derivations:<br />

xP 0 n…x†P 0 n1…x† ˆnP n …x†;<br />

P 0 n…x†xP 0 n1…x† ˆnP n1 …x†;<br />

…7:16a†<br />

…7:16b†<br />

…1 x 2 †P 0 n…x† ˆnP n1 …x†nxP n …x†; …7:16c†<br />

…2n ‡ 1†P n …x† ˆP 0 n‡1…x†P 0 n1…x†:<br />

…7:16d†<br />

With the help of the recurrence <strong>for</strong>mulas (7.16) and (7.16b), it is straight<strong>for</strong>ward<br />

to establish the other three. Omitting the full details, which are left <strong>for</strong><br />

the reader, these relations can be obtained as follows:<br />

(i) di€erentiation of Eq. (7.16) with respect to x and the use of Eq. (7.16b) to<br />

eliminate P 0 n‡1…x† leads to relation (7.16a);<br />

(ii) the addition of Eqs. (7.16a) and (7.16b) immediately yields relation<br />

(7.16d);<br />

(iii) the elimination of P 0 n1…x† between Eqs. (7.16b) and (7.16a) gives relation<br />

(7.16c).<br />

Example 7.1<br />

The physical signi®cance of expansion (7.14) is apparent in this simple example:<br />

®nd the potential V of a point charge at point P due to a charge ‡q at Q.<br />

Solution:<br />

Suppose the origin is at O (Fig. 7.2). Then<br />

V P ˆ q<br />

R ˆ q…2 2r cos ‡ r 2 † 1=2 :<br />

Figure 7.2.<br />

302

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