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Mathematical Methods for Physicists: A concise introduction - Site Map

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SOME USEFUL METHODS OF INTEGRATION<br />

Some useful methods of integration<br />

(1) Changing variables: We use a simple example to illustrate this common<br />

procedure. Consider the integral<br />

I ˆ<br />

Z 1<br />

0<br />

e ax2 dx;<br />

which is equal to …=a† 1=2 =2: To show this let us write<br />

Then<br />

I 2 ˆ<br />

Z 1<br />

0<br />

I ˆ<br />

e ax2 dx<br />

Z 1<br />

0<br />

Z 1<br />

0<br />

e ax2 dx ˆ<br />

e ay2 dy ˆ<br />

Z 1<br />

0<br />

e ay2 dy:<br />

Z 1 Z 1<br />

0<br />

0<br />

e a…x2 ‡y 2† dxdy:<br />

We now rewrite the integral in plane polar coordinates …r;†:<br />

x 2 ‡ y 2 ˆ r 2 ; dxdy ˆ rdrd . Then<br />

Z 1 Z =2<br />

I 2 ˆ e ar2 rddr ˆ Z 1<br />

e ar2 rdr ˆ <br />

1<br />

ear2<br />

ˆ <br />

2<br />

2 2a 4a<br />

and<br />

0<br />

0<br />

I ˆ<br />

Z 1<br />

(2) Integration by parts: Since<br />

0<br />

0<br />

e ax2 dx ˆ…=a† 1=2 =2:<br />

d<br />

dx … uv†<br />

ˆ u dv<br />

dx ‡ v du<br />

dx ;<br />

where u ˆ f …x† and v ˆ g…x†, it follows that<br />

Z <br />

u<br />

dv Z <br />

dx ˆ uv v<br />

du <br />

dx:<br />

dx<br />

dx<br />

This can be a useful <strong>for</strong>mula in evaluating integrals.<br />

0<br />

Example A1.17<br />

Evaluate I ˆ R tan 1 xdx<br />

Solution: Since tan 1 x can be easily di€erentiated, we write<br />

I ˆ R tan 1 xdx ˆ R 1 tan 1 xdx and let u ˆ tan 1 x; dv=dx ˆ 1. Then<br />

Z<br />

I ˆ x tan 1 xdx<br />

x <br />

1 ‡ x 2 ˆ x tan1 x 1 2 log…1 ‡ x2 †‡c:<br />

531

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