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New trends in physics teaching, v.4; The ... - unesdoc - Unesco

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<strong>New</strong> Trends <strong>in</strong> Physics Teach<strong>in</strong>g IV<br />

APPENDIX<br />

When a quantity such as rate r(t) of consumption of a resource grows a fixed percentage per<br />

year, the growth is exponential.<br />

where Y, is the current rate of consumption at t = 0, e is the base of natural logarithms, k is the<br />

fractional growth per year, and t is the time <strong>in</strong> years. <strong>The</strong> grow<strong>in</strong>g quantity wil <strong>in</strong>crease to twice<br />

its <strong>in</strong>itial size <strong>in</strong> the doubl<strong>in</strong>g time T2 where<br />

T2 (yr) = (ln2) / k = 70/P, (Eq. 2)<br />

and where P, the percentage growth per year, is 100k. <strong>The</strong> total consumption of a resource<br />

between the present (t = 0) and a future time Tis<br />

=l C r(t) dt.<br />

<strong>The</strong> consumption <strong>in</strong> a steady period of growth is<br />

C = rol ekTdt<br />

If the known size of the resource is R tonnes, then we can detenn<strong>in</strong>e the exponential expiry<br />

time (EET) by f<strong>in</strong>d<strong>in</strong>g the time T, at which the total consumption C is equal to R:<br />

We may solve this for the exponential expiry time T, ,<br />

R = (r0/k)(ekT, - 1). 0%. 5)<br />

EET = T, = (l/k) In (kR/v, + 1). (Eq. 6)<br />

This equation is valid for all positive values of k and for those negative values of k for which the<br />

argument of the logarithm is positive.<br />

36

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