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Assessment and Future Directions of Nonlinear Model Predictive ...

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344 L. BlankTheorem 3. S is a linear isomorphism <strong>and</strong> with the real values A = α, C = δ,Q = q, R −1 = r we havemin(4r, qδ 2 ) ≤ ‖S‖ H 1 →(H 1 ) ′ ≤ 2r max(1,α2 )+qδ 2 , (22){ }c(α)2qδ 2 ≤‖S −1 ‖ (H 1 ) ′ →H ≤ max 1 r , 2α2 +1qδ 2 , (23)e 2H −1for large |α|. Hence for fixed regularization pa-2(e 2H +1)√with c(α) ≈|α| 3/2rameters r <strong>and</strong> qcond(S) =‖S‖ H 1 →(H 1 ) ′‖S−1 ‖ (H 1 ) ′ →H 1to infinity with |α| →∞.is bounded but tendsThe exact value <strong>of</strong> c(α) :=‖ exp(α·)‖ H 1/‖ exp(α·)‖ (H1 ) ′isc 2 (α) =(1+α 2 )(α+1) 2 (α−1) 2 (e H −e −H )(e 2αH −1)(2α+1)(α−1) 2 (e H −e −H )(e 2αH −1)+4α 3 e −H (e αH −e H ) 2 .Considering several state functions one has to take into account observability toshow positive definiteness <strong>and</strong> herewith continuity <strong>and</strong> coercivity <strong>of</strong> a.Weshortlysketch this step while refering for the other arguments to [4]. Given a(x, x) =0then x is the solution <strong>of</strong> the system ẋ − Ax ≡ 0, x(0) = x 0 <strong>and</strong> (y ≡)Cx ≡ 0.Since the system is observable y ≡ 0 yields x 0 = 0 <strong>and</strong> consequently x ≡ 0.Hence, a(x, x) > 0forx ≢ 0. Then continuity <strong>and</strong> coercivity <strong>of</strong> a yieldTheorem 4. For any z,u ∈ L 2 the solution x <strong>of</strong> the weak formulation (20)determines the unique solution <strong>of</strong> the minimization problem (18).Hence for well-posedness only the question <strong>of</strong> stability has still to be answered.Using the Riesz representation theorem [2] <strong>and</strong> considering like for one stateonly <strong>and</strong> Lemma 1b.) the exponential function we obtainTheorem 5. S : H 1 → ( H 1) ′is bounded, has a bounded inverse <strong>and</strong>0 < 2/‖R‖≤‖S‖ H 1 →(H 1 ) ′ ≤ 2‖R‖−1 max(1, ‖A‖ 2 )+‖C T QC‖, (24)max{c(α)/‖C T QCv‖ l2 }≤‖S −1 ‖ (H 1 ) ′ →H1. (25)for all normed v ∈ IR nx eigenvectors <strong>of</strong> A with real eigenvalue α. In (24) thelower bound is valid if there exists an α 2 > 1. Observability guarantees Cv ≠0.As a consequence <strong>of</strong> Theorem 5 <strong>and</strong> Lemma 1b.) we have:Corollary 2. For any fixed regularization cond(S) is large, if there exists an inmodulo large real eigenvalue <strong>of</strong> A or if there exists a real eigenvector v <strong>of</strong> Awhich is close to the null space <strong>of</strong> C. If this is the case then the observabilitymeasure is low too.Nevertheless, the boundedness <strong>of</strong> the inverse S −1 <strong>and</strong> the compact inbeddingH 1 ↩→ C 0 yieldsCorollary 3. Linear state estimation formulated as least squares problemmin 1 2(y − z)T Q(y − z)+w T R w wdt∫ H0

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