A history of Greek mathematics Vol.II from Aristarchus to Diophantus by Heath, Thomas Little, Sir, 1921
MACEDONIA is GREECE and will always be GREECE- (if they are desperate to steal a name, Monkeydonkeys suits them just fine) ΚΑΤΩ Η ΣΥΓΚΥΒΕΡΝΗΣΗ ΤΩΝ ΠΡΟΔΟΤΩΝ!!! ΦΕΚ,ΚΚΕ,ΚΝΕ,ΚΟΜΜΟΥΝΙΣΜΟΣ,ΣΥΡΙΖΑ,ΠΑΣΟΚ,ΝΕΑ ΔΗΜΟΚΡΑΤΙΑ,ΕΓΚΛΗΜΑΤΑ,ΔΑΠ-ΝΔΦΚ, MACEDONIA,ΣΥΜΜΟΡΙΤΟΠΟΛΕΜΟΣ,ΠΡΟΣΦΟΡΕΣ,ΥΠΟΥΡΓΕΙΟ,ΕΝΟΠΛΕΣ ΔΥΝΑΜΕΙΣ,ΣΤΡΑΤΟΣ, ΑΕΡΟΠΟΡΙΑ,ΑΣΤΥΝΟΜΙΑ,ΔΗΜΑΡΧΕΙΟ,ΝΟΜΑΡΧΙΑ,ΠΑΝΕΠΙΣΤΗΜΙΟ,ΛΟΓΟΤΕΧΝΙΑ,ΔΗΜΟΣ,LIFO,ΛΑΡΙΣΑ, ΠΕΡΙΦΕΡΕΙΑ,ΕΚΚΛΗΣΙΑ,ΟΝΝΕΔ,ΜΟΝΗ,ΠΑΤΡΙΑΡΧΕΙΟ,ΜΕΣΗ ΕΚΠΑΙΔΕΥΣΗ,ΙΑΤΡΙΚΗ,ΟΛΜΕ,ΑΕΚ,ΠΑΟΚ,ΦΙΛΟΛΟΓΙΚΑ,ΝΟΜΟΘΕΣΙΑ,ΔΙΚΗΓΟΡΙΚΟΣ,ΕΠΙΠΛΟ, ΣΥΜΒΟΛΑΙΟΓΡΑΦΙΚΟΣ,ΕΛΛΗΝΙΚΑ,ΜΑΘΗΜΑΤΙΚΑ,ΝΕΟΛΑΙΑ,ΟΙΚΟΝΟΜΙΚΑ,ΙΣΤΟΡΙΑ,ΙΣΤΟΡΙΚΑ,ΑΥΓΗ,ΤΑ ΝΕΑ,ΕΘΝΟΣ,ΣΟΣΙΑΛΙΣΜΟΣ,LEFT,ΕΦΗΜΕΡΙΔΑ,ΚΟΚΚΙΝΟ,ATHENS VOICE,ΧΡΗΜΑ,ΟΙΚΟΝΟΜΙΑ,ΕΝΕΡΓΕΙΑ, ΡΑΤΣΙΣΜΟΣ,ΠΡΟΣΦΥΓΕΣ,GREECE,ΚΟΣΜΟΣ,ΜΑΓΕΙΡΙΚΗ,ΣΥΝΤΑΓΕΣ,ΕΛΛΗΝΙΣΜΟΣ,ΕΛΛΑΔΑ, ΕΜΦΥΛΙΟΣ,ΤΗΛΕΟΡΑΣΗ,ΕΓΚΥΚΛΙΟΣ,ΡΑΔΙΟΦΩΝΟ,ΓΥΜΝΑΣΤΙΚΗ,ΑΓΡΟΤΙΚΗ,ΟΛΥΜΠΙΑΚΟΣ, ΜΥΤΙΛΗΝΗ,ΧΙΟΣ,ΣΑΜΟΣ,ΠΑΤΡΙΔΑ,ΒΙΒΛΙΟ,ΕΡΕΥΝΑ,ΠΟΛΙΤΙΚΗ,ΚΥΝΗΓΕΤΙΚΑ,ΚΥΝΗΓΙ,ΘΡΙΛΕΡ, ΠΕΡΙΟΔΙΚΟ,ΤΕΥΧΟΣ,ΜΥΘΙΣΤΟΡΗΜΑ,ΑΔΩΝΙΣ ΓΕΩΡΓΙΑΔΗΣ,GEORGIADIS,ΦΑΝΤΑΣΤΙΚΕΣ ΙΣΤΟΡΙΕΣ, ΑΣΤΥΝΟΜΙΚΑ,ΦΙΛΟΣΟΦΙΚΗ,ΦΙΛΟΣΟΦΙΚΑ,ΙΚΕΑ,ΜΑΚΕΔΟΝΙΑ,ΑΤΤΙΚΗ,ΘΡΑΚΗ,ΘΕΣΣΑΛΟΝΙΚΗ,ΠΑΤΡΑ, ΙΟΝΙΟ,ΚΕΡΚΥΡΑ,ΚΩΣ,ΡΟΔΟΣ,ΚΑΒΑΛΑ,ΜΟΔΑ,ΔΡΑΜΑ,ΣΕΡΡΕΣ,ΕΥΡΥΤΑΝΙΑ,ΠΑΡΓΑ,ΚΕΦΑΛΟΝΙΑ, ΙΩΑΝΝΙΝΑ,ΛΕΥΚΑΔΑ,ΣΠΑΡΤΗ,ΠΑΞΟΙ
MACEDONIA is GREECE and will always be GREECE- (if they are desperate to steal a name, Monkeydonkeys suits them just fine)
ΚΑΤΩ Η ΣΥΓΚΥΒΕΡΝΗΣΗ ΤΩΝ ΠΡΟΔΟΤΩΝ!!!
ΦΕΚ,ΚΚΕ,ΚΝΕ,ΚΟΜΜΟΥΝΙΣΜΟΣ,ΣΥΡΙΖΑ,ΠΑΣΟΚ,ΝΕΑ ΔΗΜΟΚΡΑΤΙΑ,ΕΓΚΛΗΜΑΤΑ,ΔΑΠ-ΝΔΦΚ, MACEDONIA,ΣΥΜΜΟΡΙΤΟΠΟΛΕΜΟΣ,ΠΡΟΣΦΟΡΕΣ,ΥΠΟΥΡΓΕΙΟ,ΕΝΟΠΛΕΣ ΔΥΝΑΜΕΙΣ,ΣΤΡΑΤΟΣ, ΑΕΡΟΠΟΡΙΑ,ΑΣΤΥΝΟΜΙΑ,ΔΗΜΑΡΧΕΙΟ,ΝΟΜΑΡΧΙΑ,ΠΑΝΕΠΙΣΤΗΜΙΟ,ΛΟΓΟΤΕΧΝΙΑ,ΔΗΜΟΣ,LIFO,ΛΑΡΙΣΑ, ΠΕΡΙΦΕΡΕΙΑ,ΕΚΚΛΗΣΙΑ,ΟΝΝΕΔ,ΜΟΝΗ,ΠΑΤΡΙΑΡΧΕΙΟ,ΜΕΣΗ ΕΚΠΑΙΔΕΥΣΗ,ΙΑΤΡΙΚΗ,ΟΛΜΕ,ΑΕΚ,ΠΑΟΚ,ΦΙΛΟΛΟΓΙΚΑ,ΝΟΜΟΘΕΣΙΑ,ΔΙΚΗΓΟΡΙΚΟΣ,ΕΠΙΠΛΟ, ΣΥΜΒΟΛΑΙΟΓΡΑΦΙΚΟΣ,ΕΛΛΗΝΙΚΑ,ΜΑΘΗΜΑΤΙΚΑ,ΝΕΟΛΑΙΑ,ΟΙΚΟΝΟΜΙΚΑ,ΙΣΤΟΡΙΑ,ΙΣΤΟΡΙΚΑ,ΑΥΓΗ,ΤΑ ΝΕΑ,ΕΘΝΟΣ,ΣΟΣΙΑΛΙΣΜΟΣ,LEFT,ΕΦΗΜΕΡΙΔΑ,ΚΟΚΚΙΝΟ,ATHENS VOICE,ΧΡΗΜΑ,ΟΙΚΟΝΟΜΙΑ,ΕΝΕΡΓΕΙΑ, ΡΑΤΣΙΣΜΟΣ,ΠΡΟΣΦΥΓΕΣ,GREECE,ΚΟΣΜΟΣ,ΜΑΓΕΙΡΙΚΗ,ΣΥΝΤΑΓΕΣ,ΕΛΛΗΝΙΣΜΟΣ,ΕΛΛΑΔΑ, ΕΜΦΥΛΙΟΣ,ΤΗΛΕΟΡΑΣΗ,ΕΓΚΥΚΛΙΟΣ,ΡΑΔΙΟΦΩΝΟ,ΓΥΜΝΑΣΤΙΚΗ,ΑΓΡΟΤΙΚΗ,ΟΛΥΜΠΙΑΚΟΣ, ΜΥΤΙΛΗΝΗ,ΧΙΟΣ,ΣΑΜΟΣ,ΠΑΤΡΙΔΑ,ΒΙΒΛΙΟ,ΕΡΕΥΝΑ,ΠΟΛΙΤΙΚΗ,ΚΥΝΗΓΕΤΙΚΑ,ΚΥΝΗΓΙ,ΘΡΙΛΕΡ, ΠΕΡΙΟΔΙΚΟ,ΤΕΥΧΟΣ,ΜΥΘΙΣΤΟΡΗΜΑ,ΑΔΩΝΙΣ ΓΕΩΡΓΙΑΔΗΣ,GEORGIADIS,ΦΑΝΤΑΣΤΙΚΕΣ ΙΣΤΟΡΙΕΣ, ΑΣΤΥΝΟΜΙΚΑ,ΦΙΛΟΣΟΦΙΚΗ,ΦΙΛΟΣΟΦΙΚΑ,ΙΚΕΑ,ΜΑΚΕΔΟΝΙΑ,ΑΤΤΙΚΗ,ΘΡΑΚΗ,ΘΕΣΣΑΛΟΝΙΚΗ,ΠΑΤΡΑ, ΙΟΝΙΟ,ΚΕΡΚΥΡΑ,ΚΩΣ,ΡΟΔΟΣ,ΚΑΒΑΛΑ,ΜΟΔΑ,ΔΡΑΜΑ,ΣΕΡΡΕΣ,ΕΥΡΥΤΑΝΙΑ,ΠΑΡΓΑ,ΚΕΦΑΛΟΝΙΑ, ΙΩΑΝΝΙΝΑ,ΛΕΥΚΑΔΑ,ΣΠΑΡΤΗ,ΠΑΞΟΙ
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THE COLLECTION. BOOK IV 381<br />
Hence / lies on a certain curve.<br />
Therefore E, its projection<br />
on the plane ABO, also lies on a curve.<br />
In the particular case where the given ratio <strong>of</strong> EF <strong>to</strong> the<br />
arc CD is equal <strong>to</strong> the ratio <strong>of</strong> BA <strong>to</strong> the arc CA, the locus <strong>of</strong><br />
E is a quadratrix.<br />
[The surface described <strong>by</strong> the straight line LH is a plec<strong>to</strong>id.<br />
The shape <strong>of</strong> it is perhaps best realized as a continuous spiral<br />
staircase, i.e. a spiral staircase with infinitely small steps.<br />
The quadratrix is thus produced as the orthogonal projection<br />
<strong>of</strong> the curve in which the plec<strong>to</strong>id is intersected <strong>by</strong> a plane<br />
through BC inclined at a given angle <strong>to</strong> the plane ABC. It is<br />
not difficult <strong>to</strong> verify the result analytically.]<br />
(2) The second method uses a right cylinder the base <strong>of</strong> which<br />
is an Archimedean spiral.<br />
Let ABC be a quadrant <strong>of</strong> a circle, as before, and EF, perpendicular<br />
at F <strong>to</strong> BC, a straight<br />
line <strong>of</strong> such length that EF is<br />
<strong>to</strong> the arc DC as AB is <strong>to</strong> the<br />
arc ADC.«<br />
Let a point on AB move uniformly<br />
<strong>from</strong> A <strong>to</strong> B while, in the<br />
same time, AB itself revolves<br />
uniformly about B <strong>from</strong> the position BA <strong>to</strong> the position BC.<br />
The point thus describes the spiral AGB. If the spiral cuts<br />
BD in G,<br />
or BG :<br />
BA:BG = (arc ADC) :<br />
(arc DC) = BA :<br />
(arc ADC).<br />
(arc DC),<br />
Therefore BG = EF.<br />
Draw GK at right angles <strong>to</strong> the plane ABC and equal <strong>to</strong> BG.<br />
Then GK, and therefore K, lies on a right cylinder with the<br />
spiral as base.<br />
But BK also lies on a conical surface with vertex B such that<br />
its genera<strong>to</strong>rs all make an angle <strong>of</strong> \tt with the plane ABC.<br />
Consequently K lies on the intersection <strong>of</strong> two surfaces,<br />
and therefore on a curve.<br />
Through K draw LK1 parallel <strong>to</strong> BD, and let BL, EI be at<br />
right angles <strong>to</strong> the plane ABC.<br />
Then LKI, moving always parallel <strong>to</strong> the plane ABC, with<br />
one extremity on BL and passing through K on a certain<br />
382 PAPPUS OF ALEXANDRIA<br />
curve, describes a certain plec<strong>to</strong>id, which therefore contains the<br />
point /.<br />
Also IE = EF, IF is perpendicular <strong>to</strong> BG, and hence IF, and<br />
therefore 7, lies on a fixed plane through BG inclined <strong>to</strong> ABG<br />
at an angle <strong>of</strong> ^w.<br />
Therefore I, lying on the intersection <strong>of</strong> the plec<strong>to</strong>id and the<br />
said plane, lies on a certain curve. So therefore does the<br />
projection <strong>of</strong> I on ABG, i.e. the point E.<br />
The locus <strong>of</strong> E is clearly the quadratrix.<br />
[This result can also be verified analytically.]<br />
(S) Digression: a spiral on a sphere.<br />
Prop. 30 (chap. 35) is a digression on the subject <strong>of</strong> a certain<br />
spiral described on a sphere, suggested <strong>by</strong> the discussion <strong>of</strong><br />
a spiral in a plane.<br />
Take a hemisphere bounded <strong>by</strong> the great circle KLM,<br />
with H as pole. Suppose that the quadrant <strong>of</strong> a great circle<br />
HNK revolves uniformly about the radius HO so that K<br />
describes the circle KLM and returns <strong>to</strong> its original position<br />
at K, and suppose that a point moves uniformly at the same<br />
time <strong>from</strong> H <strong>to</strong><br />
K at such speed that the point arrives at K<br />
at the same time that HK resumes its original position. The<br />
point will thus describe a spiral on the surface <strong>of</strong> the sphere<br />
between the points H and K as shown in the figure.<br />
Pappus then sets himself <strong>to</strong> prove that the portion <strong>of</strong> the<br />
surface <strong>of</strong> the sphere cut <strong>of</strong>f <strong>to</strong>wards the pole between the<br />
spiral and the arc HNK is <strong>to</strong> the surface <strong>of</strong> the hemisphere in