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Linear Algebra, 2020a

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90 Chapter Two. Vector Spaces<br />

Addition and scalar multiplication are component-wise, as in Example 1.4. (We<br />

can formalize “infinitely-tall” by saying that it means an infinite sequence, or<br />

that it means a function from N to R.)<br />

1.11 Example The set of polynomials with real coefficients<br />

{a 0 + a 1 x + ···+ a n x n | n ∈ N and a 0 ,...,a n ∈ R}<br />

makes a vector space when given the natural ‘+’<br />

(a 0 + a 1 x + ···+ a n x n )+(b 0 + b 1 x + ···+ b n x n )<br />

=(a 0 + b 0 )+(a 1 + b 1 )x + ···+(a n + b n )x n<br />

and ‘·’.<br />

r · (a 0 + a 1 x + ...a n x n )=(ra 0 )+(ra 1 )x + ...(ra n )x n<br />

This space differs from the space P 3 of Example 1.8. This space contains<br />

not just degree three polynomials, but degree thirty polynomials and degree<br />

three hundred polynomials, too. Each individual polynomial of course is of a<br />

finite degree, but the set has no single bound on the degree of all of its members.<br />

We can think of this example, like the prior one, in terms of infinite-tuples.<br />

For instance, we can think of 1 + 3x + 5x 2 as corresponding to (1,3,5,0,0,...).<br />

However, this space differs from the one in Example 1.10. Here, each member of<br />

the set has a finite degree, that is, under the correspondence there is no element<br />

from this space matching (1, 2, 5, 10, . . . ). Vectors in this space correspond to<br />

infinite-tuples that end in zeroes.<br />

1.12 Example The set {f | f: R → R} of all real-valued functions of one real<br />

variable is a vector space under these.<br />

(f 1 + f 2 )(x) =f 1 (x)+f 2 (x) (r · f)(x) =rf(x)<br />

The difference between this and Example 1.10 is the domain of the functions.<br />

1.13 Example The set F = {a cos θ + b sin θ | a, b ∈ R} of real-valued functions of<br />

the real variable θ is a vector space under the operations<br />

(a 1 cos θ + b 1 sin θ)+(a 2 cos θ + b 2 sin θ) =(a 1 + a 2 ) cos θ +(b 1 + b 2 ) sin θ<br />

and<br />

r · (a cos θ + b sin θ) =(ra) cos θ +(rb) sin θ<br />

inherited from the space in the prior example. (We can think of F as “the same”<br />

as R 2 in that a cos θ + b sin θ corresponds to the vector with components a and<br />

b.)

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