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Linear Algebra, 2020a

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Section IV. Jordan Form 451<br />

and to move from the upper right to the lower right we multiply by this matrix.<br />

( ) −1 ( )<br />

1 −2 1/2 1/2<br />

P =<br />

=<br />

1 2 −1/4 1/4<br />

So this equation shows the similarity.<br />

( )(<br />

1/2 1/2 2 −1<br />

−1/4 1/4 1 4<br />

)(<br />

)<br />

1 −2<br />

1 2<br />

(<br />

=<br />

3 0<br />

1 3<br />

)<br />

2.5 Example This matrix<br />

⎛<br />

⎞<br />

4 1 0 −1<br />

0 3 0 1<br />

T = ⎜<br />

⎟<br />

⎝0 0 4 0 ⎠<br />

1 0 0 5<br />

has characteristic polynomial (x − 4) 4 and so has the single eigenvalue 4.<br />

power p (T − 4I) p N ((T − 4I) p )<br />

⎛<br />

⎞ ⎛ ⎞<br />

0 1 0 −1 −w<br />

1<br />

0 −1 0 1<br />

⎜<br />

⎟ {<br />

w<br />

⎜ ⎟ | z, w ∈ C}<br />

⎝0 0 0 0 ⎠ ⎝ z ⎠<br />

1 0 0 1 w<br />

⎛<br />

⎞ ⎛ ⎞<br />

−1 −1 0 0 −y<br />

2<br />

1 1 0 0<br />

⎜<br />

⎟<br />

⎝ 0 0 0 0⎠<br />

{ y<br />

⎜ ⎟ | y, z, w ∈ C}<br />

⎝ z ⎠<br />

1 1 0 0 w<br />

⎛<br />

⎞ ⎛ ⎞<br />

0 0 0 0 x<br />

3<br />

0 0 0 0<br />

⎜<br />

⎟ {<br />

y<br />

⎜ ⎟ | x, y, z, w ∈ C}<br />

⎝0 0 0 0⎠<br />

⎝ z ⎠<br />

0 0 0 0 w<br />

The null space of t−4 has dimension two, the null space of (t−4) 2 has dimension<br />

three, and the null space of (t − 4) 3 has dimension four. This gives the canonical<br />

form for t − 4.<br />

⎛<br />

⎞<br />

0 0 0 0<br />

1 0 0 0<br />

N = Rep B,B (t − 4) = ⎜<br />

⎟<br />

⎝0 1 0 0⎠<br />

0 0 0 0<br />

⃗β 1<br />

t−4<br />

↦−−→ ⃗β 2<br />

t−4<br />

t−4<br />

↦−−→ ⃗β 3 ↦−−→ ⃗0<br />

t−4<br />

⃗β 4 ↦−−→ ⃗0

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