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Linear Algebra, 2020a

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Section III. Computing <strong>Linear</strong> Maps 217<br />

We can illustrate Theorem 1.5 by computing the matrix-vector product representing<br />

this action by the projection map.<br />

⎛<br />

⎜<br />

2<br />

⎞<br />

( )<br />

⎟ 2<br />

π( ⎝2⎠) =<br />

2<br />

1<br />

Represent the domain vector with respect to the domain’s basis<br />

⎛ ⎞ ⎛<br />

2<br />

⎜ ⎟ ⎜<br />

1<br />

⎞<br />

⎟<br />

Rep B ( ⎝2⎠) = ⎝2⎠<br />

1 1<br />

to get this matrix-vector product.<br />

⎛<br />

⎜<br />

2<br />

⎞<br />

(<br />

)<br />

⎟ 1 0 −1<br />

Rep D ( π( ⎝2⎠))=<br />

−1 1 1<br />

1<br />

B<br />

B,D<br />

⎛<br />

⎜<br />

1<br />

⎞<br />

⎟<br />

⎝2⎠<br />

1<br />

Expanding this into a linear combination of vectors from D<br />

( ) ( ) ( )<br />

2 1 2<br />

0 · + 2 · =<br />

1 1 2<br />

B<br />

( )<br />

0<br />

=<br />

2<br />

checks that the map’s action is indeed reflected in the operation of the matrix.<br />

We will sometimes compress these three displayed equations into one.<br />

⎛<br />

⎜<br />

2<br />

⎞ ⎛<br />

⎟ ⎜<br />

1<br />

⎞<br />

( ) ( )<br />

⎟ h 0 2<br />

⎝2⎠ = ⎝2⎠<br />

↦−→ =<br />

H 2 2<br />

1 1<br />

D<br />

B<br />

We now have two ways to compute the effect of projection, the straightforward<br />

formula that drops each three-tall vector’s third component to make a two-tall<br />

vector, and the above formula that uses representations and matrix-vector<br />

multiplication. The second way may seem complicated compared to the first,<br />

but it has advantages. The next example shows that for some maps this new<br />

scheme simplifies the formula.<br />

1.10 Example To represent a rotation map t θ : R 2 → R 2 that turns all vectors in<br />

the plane counterclockwise through an angle θ<br />

D<br />

⃗u<br />

t π/6<br />

−→<br />

t π/6 (⃗u)

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