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Linear Algebra, 2020a

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254 Chapter Three. Maps Between Spaces<br />

(b) Matrix multiplication is associative, so in computing H 1 H 2 H 3 H 4 we can expect<br />

to get the same answer no matter where we put the parentheses. The cost in<br />

number of multiplications, however, varies. Find the association requiring the<br />

fewest real number multiplications to compute the matrix product of a 5×10<br />

matrix, a 10×20 matrix, a 20×5 matrix, and a 5×1 matrix. Use the same formula<br />

as in the prior part.<br />

(c) (Very hard.) Find a way to multiply two 2×2 matrices using only seven<br />

multiplications instead of the eight suggested by the prior approach.<br />

? 3.49 [Putnam, 1990, A-5] IfA and B are square matrices of the same size such that<br />

ABAB = 0, does it follow that BABA = 0?<br />

3.50 [Am. Math. Mon., Dec. 1966] Demonstrate these four assertions to get an alternate<br />

proof that column rank equals row rank.<br />

(a) ⃗y · ⃗y = 0 iff ⃗y = ⃗0.<br />

(b) A⃗x = ⃗0 iff A T A⃗x = ⃗0.<br />

(c) dim(R(A)) = dim(R(A T A)).<br />

(d) col rank(A) =col rank(A T )=row rank(A).<br />

3.51 [Ackerson] Prove (where A is an n×n matrix and so defines a transformation of<br />

any n-dimensional space V with respect to B, B where B is a basis) that dim(R(A)∩<br />

N (A)) = dim(R(A)) − dim(R(A 2 )). Conclude<br />

(a) N (A) ⊂ R(A) iff dim(N (A)) = dim(R(A)) − dim(R(A 2 ));<br />

(b) R(A) ⊆ N (A) iff A 2 = 0;<br />

(c) R(A) =N (A) iff A 2 = 0 and dim(N (A)) = dim(R(A)) ;<br />

(d) dim(R(A) ∩ N (A)) = 0 iff dim(R(A)) = dim(R(A 2 )) ;<br />

(e) (Requires the Direct Sum subsection, which is optional.) V = R(A) ⊕ N (A)<br />

iff dim(R(A)) = dim(R(A 2 )).<br />

IV.4<br />

Inverses<br />

We finish this section by considering how to represent the inverse of a linear map.<br />

We first recall some things about inverses. Where π: R 3 → R 2 is the projection<br />

map and ι: R 2 → R 3 is the embedding<br />

⎛ ⎞<br />

⎛ ⎞<br />

x<br />

⎜ ⎟<br />

⎝y⎠<br />

z<br />

π<br />

↦−→<br />

(<br />

x<br />

y<br />

) (<br />

x<br />

y<br />

)<br />

ι<br />

↦−→<br />

x<br />

⎜ ⎟<br />

⎝y⎠<br />

0<br />

then the composition π ◦ ι is the identity map π ◦ ι = id on R 2 .<br />

⎛ ⎞<br />

( ) x ( )<br />

x ι ⎜ ⎟<br />

↦−→ ⎝y⎠<br />

↦−→<br />

π x<br />

y<br />

y<br />

0

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