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Linear Algebra, 2020a

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196 Chapter Three. Maps Between Spaces<br />

operations. Let f, g: V → W be linear. Then the operation of function addition<br />

is preserved<br />

(f + g)(c 1 ⃗v 1 + c 2 ⃗v 2 )=f(c 1 ⃗v 1 + c 2 ⃗v 2 )+g(c 1 ⃗v 1 + c 2 ⃗v 2 )<br />

= c 1 f(⃗v 1 )+c 2 f(⃗v 2 )+c 1 g(⃗v 1 )+c 2 g(⃗v 2 )<br />

( ) ( )<br />

= c 1 f + g (⃗v1 )+c 2 f + g (⃗v2 )<br />

as is the operation of scalar multiplication of a function.<br />

Hence L(V, W) is a subspace.<br />

(r · f)(c 1 ⃗v 1 + c 2 ⃗v 2 )=r(c 1 f(⃗v 1 )+c 2 f(⃗v 2 ))<br />

= c 1 (r · f)(⃗v 1 )+c 2 (r · f)(⃗v 2 )<br />

QED<br />

We started this section by defining ‘homomorphism’ as a generalization of<br />

‘isomorphism’, by isolating the structure preservation property. Some of the<br />

points about isomorphisms carried over unchanged, while we adapted others.<br />

Note, however, that the idea of ‘homomorphism’ is in no way somehow<br />

secondary to that of ‘isomorphism’. In the rest of this chapter we shall work<br />

mostly with homomorphisms. This is partly because any statement made about<br />

homomorphisms is automatically true about isomorphisms but more because,<br />

while the isomorphism concept is more natural, our experience will show that<br />

the homomorphism concept is more fruitful and more central to progress.<br />

Exercises<br />

̌ 1.18 Decide ⎛ if ⎞each h: R 3 → R 2 is linear. ⎛ ⎞<br />

⎛ ⎞<br />

x ( )<br />

x ( x (<br />

(a) h( ⎝<br />

x<br />

y⎠) =<br />

(b) h( ⎝ 0<br />

y⎠) = (c) h( ⎝ 1<br />

y⎠) =<br />

x + y + z<br />

0)<br />

1)<br />

z<br />

z<br />

z<br />

⎛ ⎞<br />

x ( )<br />

(d) h( ⎝ 2x + y<br />

y⎠) =<br />

3y − 4z<br />

z<br />

̌ 1.19 Decide if each map h: M 2×2 → R is linear.<br />

( ) a b<br />

(a) h( )=a + d<br />

c d<br />

( ) a b<br />

(b) h( )=ad − bc<br />

c d<br />

( ) a b<br />

(c) h( )=2a + 3b + c − d<br />

c d<br />

( ) a b<br />

(d) h( )=a 2 + b 2<br />

c d<br />

̌ 1.20 Show that these are homomorphisms. Are they inverse to each other?<br />

(a) d/dx: P 3 → P 2 given by a 0 + a 1 x + a 2 x 2 + a 3 x 3 maps to a 1 + 2a 2 x + 3a 3 x 2<br />

(b) ∫ : P 2 → P 3 given by b 0 + b 1 x + b 2 x 2 maps to b 0 x +(b 1 /2)x 2 +(b 2 /3)x 3

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