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Linear Algebra, 2020a

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400 Chapter Five. Similarity<br />

1.8 Example Because of uniqueness we know, without multiplying them out, that<br />

(x + 3) 2 (x 2 + 1) 3 does not equal (x + 3) 4 (x 2 + x + 1) 2 .<br />

1.9 Example By uniqueness, if c(x) =m(x)·q(x) then where c(x) =(x−3) 2 (x+2) 3<br />

and m(x) =(x − 3)(x + 2) 2 , we know that q(x) =(x − 3)(x + 2).<br />

While x 2 +1 has no real roots and so doesn’t factor over the real numbers, if we<br />

imagine a root — traditionally denoted i, so that i 2 + 1 = 0 — then x 2 + 1 factors<br />

into a product of linears (x−i)(x+i). When we adjoin this root i to the reals and<br />

close the new system with respect to addition and multiplication then we have<br />

the complex numbers C = {a + bi | a, b ∈ R and i 2 =−1}. (These are often<br />

pictured on a plane with a plotted on the horizontal axis and b on the vertical;<br />

note that the distance of the point from the origin is |a + bi| = √ a 2 + b 2 .)<br />

In C all quadratics factor. That is, in contrast with the reals, C has no<br />

irreducible quadratics.<br />

ax 2 + bx + c = a · (x<br />

− −b + √ b 2 − 4ac<br />

2a<br />

) ( −b − √ b 2 − 4ac)<br />

· x −<br />

2a<br />

1.10 Example The second degree polynomial x 2 + x + 1 factors over the complex<br />

numbers into the product of two first degree polynomials.<br />

(<br />

x −<br />

−1 + √ −3<br />

2<br />

)( −1 − √ √<br />

−3) ( 1 3<br />

x − = x −(−<br />

2<br />

2 + 2 i))( x −(− 1 √<br />

3<br />

2 − 2 i))<br />

1.11 Theorem (Fundamental Theorem of <strong>Algebra</strong>) Polynomials with complex coefficients<br />

factor into linear polynomials with complex coefficients. The factorization<br />

is unique.<br />

I.2 Complex Representations<br />

Recall the definitions of the complex number addition<br />

and multiplication.<br />

(a + bi) +(c + di) =(a + c)+(b + d)i<br />

(a + bi)(c + di) =ac + adi + bci + bd(−1)<br />

=(ac − bd)+(ad + bc)i<br />

2.1 Example For instance, (1 − 2i) +(5 + 4i) =6 + 2i and (2 − 3i)(4 − 0.5i) =<br />

6.5 − 13i.

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