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Linear Algebra, 2020a

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Section V. Change of Basis 263<br />

1.2 Remark A better name would be ‘change of representation matrix’ but the<br />

above name is standard.<br />

The next result supports the definition.<br />

1.3 Lemma To convert from the representation of a vector ⃗v with respect to B<br />

to its representation with respect to D use the change of basis matrix.<br />

Rep B,D (id) Rep B (⃗v) =Rep D (⃗v)<br />

Conversely, if left-multiplication by a matrix changes bases M · Rep B (⃗v) =<br />

Rep D (⃗v) then M is a change of basis matrix.<br />

Proof The first sentence holds because matrix-vector multiplication represents<br />

a map application and so Rep B,D (id) · Rep B (⃗v) =Rep D ( id(⃗v))=Rep D (⃗v) for<br />

each ⃗v. For the second sentence, with respect to B, D the matrix M represents<br />

a linear map whose action is to map each vector to itself, and is therefore the<br />

identity map.<br />

QED<br />

1.4 Example With these bases for R 2 ,<br />

( ) ( ) ( ) ( )<br />

2 1<br />

−1 1<br />

B = 〈 , 〉 D = 〈 , 〉<br />

1 0<br />

1 1<br />

because<br />

( ) ( )<br />

2 −1/2<br />

Rep D ( id( )) =<br />

1 3/2<br />

D<br />

( ) ( )<br />

1 −1/2<br />

Rep D ( id( )) =<br />

0 1/2<br />

D<br />

the change of basis matrix is this.<br />

Rep B,D (id) =<br />

(<br />

)<br />

−1/2 −1/2<br />

3/2 1/2<br />

For instance, this is the representation of ⃗e 2<br />

( ) ( )<br />

0 1<br />

Rep B ( )=<br />

1 −2<br />

and the matrix does the conversion.<br />

(<br />

−1/2 −1/2<br />

3/2 1/2<br />

)(<br />

)<br />

1<br />

−2<br />

(<br />

=<br />

1/2<br />

1/2<br />

Checking that vector on the right is Rep D (⃗e 2 ) is easy.<br />

)

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