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Linear Algebra, 2020a

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Section II. Homomorphisms 199<br />

1.40 Prove that the restriction of a homomorphism to a subspace of its domain is<br />

another homomorphism.<br />

1.41 Assume that h: V → W is linear.<br />

(a) Show that the range space of this map {h(⃗v) | ⃗v ∈ V } is a subspace of the<br />

codomain W.<br />

(b) Show that the null space of this map {⃗v ∈ V | h(⃗v) =⃗0 W } is a subspace of the<br />

domain V.<br />

(c) Show that if U is a subspace of the domain V then its image {h(⃗u) | ⃗u ∈ U} is<br />

a subspace of the codomain W. This generalizes the first item.<br />

(d) Generalize the second item.<br />

1.42 Consider the set of isomorphisms from a vector space to itself. Is this a subspace<br />

of the space L(V, V) of homomorphisms from the space to itself?<br />

1.43 Does Theorem 1.9 need that 〈⃗β 1 ,...,⃗β n 〉 is a basis? That is, can we still get a<br />

well-defined and unique homomorphism if we drop either the condition that the<br />

set of ⃗β’s be linearly independent, or the condition that it span the domain?<br />

1.44 Let V be a vector space and assume that the maps f 1 ,f 2 : V → R 1 are linear.<br />

(a) Define a map F: V → R 2 whose component functions are the given linear ones.<br />

( )<br />

f1 (⃗v)<br />

⃗v ↦→<br />

f 2 (⃗v)<br />

Show that F is linear.<br />

(b) Does the converse hold — is any linear map from V to R 2 made up of two<br />

linear component maps to R 1 ?<br />

(c) Generalize.<br />

II.2<br />

Range Space and Null Space<br />

Isomorphisms and homomorphisms both preserve structure. The difference is<br />

that homomorphisms have fewer restrictions, since they needn’t be onto and<br />

needn’t be one-to-one. We will examine what can happen with homomorphisms<br />

that cannot happen with isomorphisms.<br />

First consider the fact that homomorphisms need not be onto. Of course,<br />

each function is onto some set, namely its range. For example, the injection<br />

map ι: R 2 → R 3 ⎛ ⎞<br />

( ) x<br />

x ⎜ ⎟<br />

↦→ ⎝y⎠<br />

y<br />

0<br />

is a homomorphism, and is not onto R 3 . But it is onto the xy-plane.

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