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Linear Algebra, 2020a

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412 Chapter Five. Similarity<br />

is a bit jarring because for P we must take the first matrix, which is shown as an<br />

inverse, and for P −1 we take the inverse of the first matrix, so that the two −1<br />

powers cancel and this matrix is shown without a superscript −1.<br />

(a) Check that this nicer-appearing equation holds.<br />

( ) ( )( )( ) −1<br />

3 0 1 1 3 2 1 1<br />

=<br />

0 1 0 −1 0 1 0 −1<br />

(b) Is the previous item a coincidence? Or can we always switch the P and the<br />

P −1 ?<br />

2.16 Show that the P used to diagonalize in Example 2.5 is not unique.<br />

2.17 Find a formula for the powers of this matrix. Hint: see Exercise 11.<br />

( ) −3 1<br />

−4 2<br />

2.18 We can ask how diagonalization interacts with the matrix operations. Assume<br />

that t, s: V → V are each diagonalizable. Is ct diagonalizable for all scalars c?<br />

What about t + s? t ◦ s?<br />

2.19 Show that matrices of this form are not diagonalizable.<br />

( ) 1 c<br />

c ≠ 0<br />

0 1<br />

2.20 Show<br />

(<br />

that<br />

)<br />

each of<br />

(<br />

these<br />

)<br />

is diagonalizable.<br />

1 2 x y<br />

(a)<br />

(b)<br />

x, y, z scalars<br />

2 1 y z<br />

II.3<br />

Eigenvalues and Eigenvectors<br />

We will next focus on the property of Lemma 2.4.<br />

3.1 Definition A transformation t: V → V has a scalar eigenvalue λ if there is a<br />

nonzero eigenvector ⃗ζ ∈ V such that t(⃗ζ) =λ · ⃗ζ.<br />

“Eigen” is German for “characteristic of” or “peculiar to.” Some authors call these<br />

characteristic values and vectors. No authors call them “peculiar” vectors.<br />

3.2 Example The projection map<br />

⎛ ⎞ ⎛ ⎞<br />

x<br />

⎜ ⎟<br />

⎝y⎠<br />

z<br />

π<br />

↦−→<br />

x<br />

⎜ ⎟<br />

⎝y⎠<br />

0<br />

x, y, z ∈ C<br />

has an eigenvalue of 1 associated with any eigenvector<br />

⎛ ⎞<br />

x<br />

⎜ ⎟<br />

⎝y⎠<br />

0

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