06.09.2021 Views

Linear Algebra, 2020a

Linear Algebra, 2020a

Linear Algebra, 2020a

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

Section III. Basis and Dimension 141<br />

3.14 Corollary Where the matrix A is n×n, these statements<br />

(1) the rank of A is n<br />

(2) A is nonsingular<br />

(3) the rows of A form a linearly independent set<br />

(4) the columns of A form a linearly independent set<br />

(5) any linear system whose matrix of coefficients is A has one and only one<br />

solution<br />

are equivalent.<br />

Proof Clearly (1) ⇐⇒ (2) ⇐⇒ (3) ⇐⇒ (4). The last, (4) ⇐⇒ (5), holds<br />

because a set of n column vectors is linearly independent if and only if it is a<br />

basis for R n , but the system<br />

⎛ ⎞ ⎛ ⎞ ⎛ ⎞<br />

a 1,1<br />

a 1,n d 1<br />

a 2,1<br />

c 1 ⎜<br />

⎝<br />

⎟<br />

. ⎠ + ···+ c a 2,n<br />

n ⎜ . ⎝<br />

⎟<br />

. ⎠ = d 2<br />

⎜ . ⎝<br />

⎟<br />

. ⎠<br />

a m,1 a m,n d m<br />

has a unique solution for all choices of d 1 ,...,d n ∈ R if and only if the vectors<br />

of a’s on the left form a basis.<br />

QED<br />

3.15 Remark [Munkres] Sometimes the results of this subsection are mistakenly<br />

remembered to say that the general solution of an m equations, n unknowns<br />

system uses n − m parameters. The number of equations is not the relevant<br />

number; rather, what matters is the number of independent equations, the number<br />

of equations in a maximal independent set. Where there are r independent<br />

equations, the general solution involves n − r parameters.<br />

Exercises<br />

3.16 Transpose each.<br />

⎛ ⎞<br />

( ) ( ) ( ) 0<br />

2 1 2 1 1 4 3<br />

(a)<br />

(b)<br />

(c)<br />

(d) ⎝0⎠<br />

3 1 1 3 6 7 8<br />

0<br />

(e) (−1 −2)<br />

̌ 3.17 Decide if the vector is in the row space of the matrix.<br />

⎛ ⎞<br />

( )<br />

0 1 3<br />

2 1<br />

(a) , (1 0) (b) ⎝−1 0 1⎠, (1 1 1)<br />

3 1<br />

−1 2 7<br />

̌ 3.18 Decide if the vector is in the column space.<br />

⎛<br />

⎞ ⎛ ⎞<br />

( ) ( 1 3 1 1<br />

1 1 1<br />

(a) , (b) ⎝2 0 4 ⎠, ⎝0⎠<br />

1 1 3)<br />

1 −3 −3 0<br />

̌ 3.19 Decide if the vector is in the column space of the matrix.

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!