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Linear Algebra, 2020a

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120 Chapter Two. Vector Spaces<br />

of linearly independent subsets of the given finite set until one appears with the<br />

same span as the given set.<br />

1.43 With a some calculation we can get formulas to determine whether or not a set<br />

of vectors is linearly independent.<br />

(a) Show that this subset of R 2 ( ( a b<br />

{ , }<br />

c)<br />

d)<br />

is linearly independent if and only if ad − bc ≠ 0.<br />

(b) Show that this subset of R 3 ⎛ ⎞ ⎛ ⎞ ⎛ ⎞<br />

a b c<br />

{ ⎝d⎠ , ⎝e⎠ , ⎝f⎠}<br />

g h i<br />

is linearly independent iff aei + bfg + cdh − hfa − idb − gec ≠ 0.<br />

(c) When is this subset of R 3 ⎛ ⎞ ⎛ ⎞<br />

a b<br />

{ ⎝d⎠ , ⎝e⎠}<br />

g h<br />

linearly independent?<br />

(d) This is an opinion question: for a set of four vectors from R 4 , must there be a<br />

formula involving the sixteen entries that determines independence of the set?<br />

(You needn’t produce such a formula, just decide if one exists.)<br />

̌ 1.44 (a) Prove that a set of two perpendicular nonzero vectors from R n is linearly<br />

independent when n>1.<br />

(b) What if n = 1? n = 0?<br />

(c) Generalize to more than two vectors.<br />

1.45 Consider the set of functions from the interval (−1 ... 1) ⊆ R to R.<br />

(a) Show that this set is a vector space under the usual operations.<br />

(b) Recall the formula for the sum of an infinite geometric series: 1 + x + x 2 + ···=<br />

1/(1 − x) for all x ∈ (−1..1). Why does this not express a dependence inside of<br />

the set {g(x) =1/(1 − x),f 0 (x) =1, f 1 (x) =x, f 2 (x) =x 2 ,...} (in the vector space<br />

that we are considering)? (Hint. Review the definition of linear combination.)<br />

(c) Show that the set in the prior item is linearly independent.<br />

This shows that some vector spaces exist with linearly independent subsets that<br />

are infinite.<br />

1.46 Show that, where S is a subspace of V, if a subset T of S is linearly independent<br />

in S then T is also linearly independent in V. Is that ‘only if’?

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