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Linear Algebra, 2020a

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180 Chapter Three. Maps Between Spaces<br />

to break the sum along the final ‘+’.<br />

f(c 1 ⃗v 1 + ···+ c k ⃗v k + c k+1 ⃗v k+1 )=f(c 1 ⃗v 1 + ···+ c k ⃗v k )+f(c k+1 ⃗v k+1 )<br />

Use the inductive hypothesis to break up the k-term sum on the left.<br />

Now the second half of (1) gives<br />

when applied k + 1 times.<br />

= f(c 1 ⃗v 1 )+···+ f(c k ⃗v k )+f(c k+1 ⃗v k+1 )<br />

= c 1 f(⃗v 1 )+···+ c k f(⃗v k )+c k+1 f(⃗v k+1 )<br />

QED<br />

We often use item (2) to simplify the verification that a map preserves structure.<br />

Finally, a summary. In the prior chapter, after giving the definition of a<br />

vector space, we looked at examples and noted that some spaces seemed to be<br />

essentially the same as others. Here we have defined the relation ‘ ∼ =’ and have<br />

argued that it is the right way to precisely say what we mean by “the same”<br />

because it preserves the features of interest in a vector space — in particular, it<br />

preserves linear combinations. In the next section we will show that isomorphism<br />

is an equivalence relation and so partitions the collection of vector spaces.<br />

Exercises<br />

̌ 1.12 Verify, using Example 1.4 as a model, that the two correspondences given before<br />

the definition are isomorphisms.<br />

(a) Example 1.1 (b) Example 1.2<br />

̌ 1.13 For the map f: P 1 → R 2 given by<br />

( )<br />

a + bx ↦−→<br />

f a − b<br />

b<br />

Find the image of each of these elements of the domain.<br />

(a) 3 − 2x (b) 2 + 2x (c) x<br />

Show that this map is an isomorphism.<br />

1.14 Show that the natural map f 1 from Example 1.5 is an isomorphism.<br />

1.15 Show that the map t: P 2 → P 2 given by t(ax 2 + bx + c) =bx 2 −(a + c)x + a is<br />

an isomorphism.<br />

̌ 1.16 Verify that this map is an isomorphism: h: R 4 → M 2×2 given by<br />

⎛ ⎞<br />

a<br />

( )<br />

⎜b<br />

⎟ c a+ d<br />

⎝c⎠ ↦→ b d<br />

d<br />

̌ 1.17 Decide whether each map is an isomorphism. If it is an isomorphism then prove<br />

it and if it isn’t then state a condition that it fails to satisfy.<br />

(a) f: M 2×2 → R given by<br />

( ) a b<br />

↦→ ad − bc<br />

c d

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