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Linear Algebra, 2020a

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288 Chapter Three. Maps Between Spaces<br />

N<br />

M<br />

ˆN<br />

M<br />

Notice that the projection along N is not orthogonal since there are members<br />

of the plane M that are not orthogonal to the dotted line. But the projection<br />

along ˆN is orthogonal.<br />

We have seen two projection operations, orthogonal projection into a line as<br />

well as this subsections’s projection into an M and along an N, and we naturally<br />

ask whether they are related. The right-hand picture above suggests the answer —<br />

orthogonal projection into a line is a special case of this subsection’s projection;<br />

it is projection along a subspace perpendicular to the line.<br />

N<br />

M<br />

3.4 Definition The orthogonal complement of a subspace M of R n is<br />

M ⊥ = {⃗v ∈ R n | ⃗v is perpendicular to all vectors in M}<br />

(read “M perp”). The orthogonal projection proj M (⃗v ) of a vector is its projection<br />

into M along M ⊥ .<br />

3.5 Example In R 3 , to find the orthogonal complement of the plane<br />

⎛ ⎞<br />

x<br />

⎜ ⎟<br />

P = { ⎝y⎠ | 3x + 2y − z = 0}<br />

z<br />

we start with a basis for P.<br />

⎛ ⎞ ⎛<br />

1<br />

⎜ ⎟ ⎜<br />

0<br />

⎞<br />

⎟<br />

B = 〈 ⎝0⎠ , ⎝1⎠〉<br />

3 2<br />

Any ⃗v perpendicular to every vector in B is perpendicular to every vector in the<br />

span of B (the proof of this is Exercise 22). Therefore, the subspace P ⊥ consists

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