Im Namen Allahs, des Erbarmers, des Barmherzigen - Nuur-Theorie

= m (e 2 / ε o ) 2 / L 2 = 8,4375e-67 / 5,625e-57 = 1,5 e-10 m
= L 2 f 2 k / m = 2,5e-37 / 1,6666667e-27 = 1,5 e-10 m
p V = 4.4444444 10 19 N/m 2 x 3.375 10 -30 m 3 = 1.5 10 -10 m
C v m T = 9000 x 1,66667e-27 x 1,e+13 K
= 1,5e-10 m
b k T = 1.5 10 -23 J/K x 1,e+13 K = 1.5 10 -10 m
= L / m c = 7,5e-29 ms / 5,e-19 s = 1,5e-10 m
E aee = 2,4e-29 m x 6,25e+18 = 1,5e-10 m
E kin = (t aize ) 2 / m ame = (5,e-19 s) 2 / 1,6666667e-27 = 1,5 e-10 m
= 1 1111111 e-19 / m 2 x 1,35e+9 m 3 = 1,5e-10 m
= 1500 mK / 1,e+13 K = 1,5e-10 m
= 1,35e+7 m 3 /s 2 / 9,e+16 m 2 /s 2 = 1,5e-10 m
= 6,e+26 x (5,e-19) 2 = 1,5e-10 m
= 6.10 28 m / 4 10 38 = 1.5 10 -10 m
= 100 s 2 / Kaf = 100 s 2 / 6.666667 10 11 s 2 /m = 1.5 10 -10 m
= √ ε o b k T/ e 2 n = √ 1,7066667e-28 / 7,5851851859e-9 = 1,5e-10 m
E mag = L s x I 2 = 1,46484375e-9 x (0,32s) 2 = 1,5e-10 m
E pot = Dip m x E = 2,4e-29 m x 6,25e+18 = 1,5e-10 m
E pot = µ x B = 7,2e-21 x 2,08333333 e+10 s/m = 1,5 e-10 m
= m e 4 / (L 2 x ε 2 o ) = = 1,5 e-10 m
E rot = J x ω 2 = 3,75e-47 ms 2 x 4,e+36 = 1,5 e-10 m
= 4,e+36 x ρ x r 2 x V = 1,5 e-10 m
= L 2 / J = 5,625e-57 / 3,75e-47 = 1,5 e-10 m
= √ ε o b k T / (e 2 n) = = 1,5 e-10 m
= e 2 / ε o r = 2,56e-38 / 1,7066667e-28 = 1,5 e-10 m
= m c 2 = e U = 1,6e-19 x 9,375e+8 m = 1,5 e-10 m
E aee = C U 2 = 1,706667e-28 /m x 8,7890625e+17 m 2 = 1,5 e-10 m
= e 2 / C = (1,6e-19) 2 / 1,706667e-28 /m = 1,5 e-10 m
r = m c / e B = 5, e-19 / 3,333333 e-9 = 1,5 e-10 m
= ε o r 3 x E 2 = 1,13778e-18 x 3,375e-30 x 3,90625e+37 = 1,5 e-10 m
E aee = 0,375 m / 2,5e+9 = 1,5 e-10 m
= L v 2di = e x U = = 1,5 e-10 m
= L c / e U = 1,5 e-10 m
= L 2 f 2 k / m = 1,5 e-10 m
Das Drehmoment wurde als Produkt aus wirkender Kraft F und wirksamem Kraftarm r definiert. Das
Drehmoment ist die Kraft, die zeitliche Änderung des Impulses ist. Betrag des Drehmoments:
F x r = L x ω = 7.5 10 -29 kg m 2 / s x 2,e+18 /s = 1,5 e-10 m
= I x A afe x B = 1,5 e-10 m
Die E aee entspricht der Kohärenzlänge, wenn ein Proton! eine Beschleunigungsspannung (U-
Feld)durchgelaufen hat.
= L / √m e U = 7,5e-29 ms / √ 2,5e-37 s 2 = 1,5e-10 m
= t 2 aize / m ame = 2,5e-37 / 1,666667e-27 = 1,5e-10 m
= e 2 / C Kap = 2,56e-38 / 1,7066667e-28 /m = 1,5e-10 m
= F / m ω 2 = 1 / 6,6666667e+9 /m = 1,5e-10 m
= e 2 / (m ame ε o c 2 ) = 2,56e-38 / 1,7066667e-28 /m = 1,5e-10 m
= 1 11111 e-19 / m 2 x 1,35e+9 m 3 = 1,5e-10 m
= 1,35e+7 m 3 /s 2 / 9,e+16 m 2 /s 2 = 1,5e-10 m
= 6,e+26 x (5,e-19) 2 = 1,5e-10 m
ω = L / m (e 2 / ε o) = 7,5e-29 / 3,75e-47 = 2,e+18 /s
f k = 1 / 1,5e-10 m = 6,666667e+9 1/m
/ 1 = ‏(ب)‏Ba (1,5e-10 m) 2 = 4,444444e+19 1/m 2
= 1 / (1,5e-10 m) 3 = 2,962962962e+29 1/m 3
= 1 / (1,5e-10 m) 4 = 1,9753086419753e+39 1/m 4
Asr = 1,9753086419753e+39 /m 4 x 6,25 = 1,23456790123456790e+40
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