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Pre-Phase A Report - Lisa - Nasa

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4.4 Data analysis 109<br />

that are defined in the source frame, i.e. a system with its x-axis in the x-y-plane of<br />

the barycentric frame, its z-axis pointing towards the sun and the source at its origin.<br />

The transformation is split into one transforming the source system into the barycentric<br />

system and another one from the barycentric frame into the detector frame, which is<br />

rigidly fixed to the interferometer arms.<br />

Let θ and φ be the Euler angles that define the source position in the barycentric frame,<br />

with its x-y-plane in the ecliptic, as indicated in Figure 4.9 .<br />

Sun<br />

z<br />

θ<br />

y<br />

φ<br />

Source<br />

Figure 4.9 Orientation of the source in the barycentric frame.<br />

The transformation into the source system is composed of two rotations. The first, realized<br />

by the rotation matrix a1, turns the y-axis of the barycentric frame on the projection of<br />

the line connecting sun and source on the ecliptic, that is counterclockwise through an<br />

angle φ − 90◦ around the z-axis,<br />

a1 :=<br />

⎛<br />

⎝<br />

sin φ − cos φ 0<br />

cos φ sin φ 0<br />

0 0 1<br />

x<br />

⎞<br />

⎠ . (4.61)<br />

A second rotation b1 turns the system counterclockwise around the new x-axis by 180◦−θ. With T1 := b1a1 the matrix h+ of Eq. (4.60) is transformed from the source system into<br />

the barycentric frame by<br />

h+ → T t 1 h+ T1 . (4.62)<br />

The following angles are used to calculate the transformation into the detector system :<br />

ψa := 2 πt<br />

ψb :=<br />

T<br />

1<br />

3 π ψc := −2 πt<br />

+ α (4.63)<br />

T<br />

where 1 π is the angle of LISA with respect to the ecliptic and α is the phase between<br />

3<br />

LISA’s motion around the sun and the motion around its center of mass.<br />

Now a rotation matrix a2 turns the frame of reference in the barycentric system counterclockwise<br />

around the z-axis by ψa, so the new y-axis points towards LISA. Thenb2turns it by ψb out of the ecliptic. Finally c2 turns it clockwise around the new z-axis by ψc.<br />

A vector is transformed from the barycentric into the detector system by T2 = c2b2a2.<br />

Therefore e.g. the matrix h+ is transformed as :<br />

h+ → T2 T t 1 h+ T1 T<br />

<br />

=:T<br />

t 2 . (4.64)<br />

Corrected version 2.08 3-3-1999 9:33

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