26.12.2013 Views

Coherent Backscattering from Multiple Scattering Systems - KOPS ...

Coherent Backscattering from Multiple Scattering Systems - KOPS ...

Coherent Backscattering from Multiple Scattering Systems - KOPS ...

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

5.2 The coherent backscattering cone in high resolution<br />

1<br />

3.7<br />

3.6<br />

x 10 4 0 0.2 0.4 0.6 0.8 1<br />

15 x 107 scattering angle [deg]<br />

before polarizer<br />

after polarizer<br />

1024<br />

3.5<br />

3.4<br />

intensity [a.u.]<br />

10<br />

5<br />

3.3<br />

2048 3.2<br />

1 1024 2048<br />

0<br />

Figure 5.14: Single and multiple scattering. The CCD image (left) of the backscattering<br />

of a fluidized bed shows a pronounced ring structure caused by single scattering.<br />

Calculations with Mie theory (see fig. 5.15) show, that for circularly polarized light the<br />

central maximum is extinguished by a transition through a circular polarizer after the<br />

scattering event (right; the graph was calculated using the MATLAB code <strong>from</strong> the appendix).<br />

The backscattering image however still shows an intensity maximum at the<br />

center of the ring structure, which therefore must be the coherent backscattering cone.<br />

⎛ ⎞ ⎛ ⎞ ⎛ ⎞ ⎛<br />

⎞ ⎛ ⎞ ⎛ ⎞ ⎛ ⎞<br />

S 11 + S 33<br />

1 −1 0 0 1 0 0 0 S 11 S 12 0 0 1 0 0 0 1 −1 0 0 1<br />

p = ⎜−S 11 − S 33<br />

⎟<br />

⎝ 0 ⎠ = 1 ⎜−1 1 0 0<br />

⎟<br />

2 ⎝ 0 0 0 0⎠ ·<br />

⎜0 0 0 1<br />

⎟<br />

⎝0 0 1 0⎠ ·<br />

⎜S 12 S 11 0 0<br />

⎟<br />

⎝ 0 0 S 33 S 34 ⎠ ·<br />

⎜0 0 0 1<br />

⎟<br />

⎝0 0 1 0⎠ · 1<br />

⎜−1 1 0 0<br />

⎟<br />

2 ⎝ 0 0 0 0⎠ ·<br />

⎜−1<br />

⎟<br />

⎝ 0 ⎠<br />

0<br />

0 0 0 0 0 −1 0 0 0 0 −S 34 S 33 0 −1 0 0 0 0 0 0 0<br />

p = LP · QWP · S · QWP · LP · p 0<br />

p S = S · QWP · LP · p 0<br />

⎛ ⎞ ⎛<br />

⎞ ⎛ ⎞ ⎛ ⎞ ⎛ ⎞<br />

S 11 S 11 S 12 0 0 1 0 0 0 1 −1 0 0 1<br />

p S = ⎜ S 12<br />

⎟<br />

⎝−S 34 ⎠ = ⎜S 12 S 11 0 0<br />

⎟<br />

⎝ 0 0 S 33 S 34 ⎠ ·<br />

⎜0 0 0 1<br />

⎟<br />

⎝0 0 1 0⎠ · 1<br />

⎜−1 1 0 0<br />

⎟<br />

2 ⎝ 0 0 0 0⎠ ·<br />

⎜−1<br />

⎟<br />

⎝ 0 ⎠<br />

−S 33 0 0 −S 34 S 33 0 −1 0 0 0 0 0 0 0<br />

Figure 5.15: Calculation of the Stokes vector for the experiment. Linearly polarized<br />

light with Stokes vector p 0 transmits a circular polarizer, which is represented by a<br />

combination of a linear polarizer LP and a quarter-wave-plate QWP, is scattered at the<br />

particle S, and again transmits the circular polarizer. The resulting Stokes vector p<br />

can be compared with the Stokes vector p S directly after the scatterer. The scattered<br />

intensities depicted in fig. 5.14 are given by the first elements of p and p S .<br />

63

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!