22.02.2014 Views

Naylor Road Metro Station Area Access and Capacity - WMATA.com.

Naylor Road Metro Station Area Access and Capacity - WMATA.com.

Naylor Road Metro Station Area Access and Capacity - WMATA.com.

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

Table A-6: Average Peak Hour Bus Passenger Loads at <strong>Naylor</strong> <strong>Road</strong> <strong>Station</strong><br />

(Year 2040)<br />

(J) Average<br />

Peak Hour<br />

Passenger Load<br />

per Bus<br />

(K) 2012<br />

Average Peak<br />

Hour Passenger<br />

Load<br />

(L) 2012-<br />

2040 Percent<br />

Increase in Bus<br />

Passengers<br />

(M) 2040<br />

Average Peak<br />

Hour Passenger<br />

Load<br />

Route<br />

<strong>Metro</strong>bus<br />

M2 35 105 35% 142<br />

F14 35 70 35% 95<br />

H11/12/13 35 140 35% 189<br />

C12/C14 35 84 35% 113<br />

36 35 140 35% 189<br />

39 35 140 35% 189<br />

34 35 140 35% 189<br />

TheBus<br />

32 35 70 35% 95<br />

J. Assumed average peak hour passenger load per bus at <strong>Naylor</strong> <strong>Road</strong> <strong>Station</strong><br />

K. 2012 Average Peak Hour Passenger Load = B * J<br />

L. Percent increase in bus passengers taken from Table A-3 in Appendix 3<br />

M. 2040 Average Peak Hour Passenger Load = K * (1+L)<br />

Table A-7: Bus Bays Required (Year 2040)<br />

(N) Buses<br />

per Peak<br />

Hour<br />

(O) Peak<br />

Hour<br />

Headway<br />

(minutes)<br />

(P) Average<br />

Recovery<br />

Time<br />

(minutes)<br />

(Q) Average<br />

Total Time at<br />

Bay per Bus<br />

(minutes)<br />

(R) Bays<br />

Required<br />

Route<br />

<strong>Metro</strong>bus<br />

M2 4 15 3 4 0.5<br />

F14 3 20 5 6 0.5<br />

H11/12/13 5 12 6 7 0.9<br />

C12/C14 3 20 4 5 0.5<br />

36 5 12 9 10 1.2<br />

39 5 12 0 1 0.4<br />

34 5 12 5 6 0.8<br />

TheBus<br />

32 3 20 8 9 0.7<br />

Total 33 7.0<br />

N. Buses per Peak Hour in 2040 = M / 40 (Passenger capacity per bus) [results<br />

were rounded up to the nearest whole number]<br />

O. Peak Hour Headway = 60 / N<br />

Q. Average Total Time at Bay per Bus = One-minute dwell time + P<br />

R. Bays Required by 2040 = ((Q + E) * N) / 60<br />

40 passengers. While some routes<br />

may use articulated buses, using<br />

a 40-passenger-per-bus capacity<br />

provides a more conservative<br />

estimate. To estimate the number<br />

of bays required, the same<br />

methodology employed in Table<br />

A-4 is used in Table A-7. The same<br />

average recovery time from Table A-4<br />

is assumed in Table A-7. However, in<br />

practice several variables are factored<br />

into how much time is allotted per<br />

bus at a terminal stop (e.g. restroom<br />

or meal breaks, scheduling needs,<br />

etc.).<br />

Table A-8 reveals the final<br />

calculations of the analysis to<br />

estimate the bus bay utilization in<br />

2040. Calculations in Table A-8 are<br />

similar to those in Table A-5. Table<br />

A-8 proposes new bus bay route<br />

assignments for seven bays (six<br />

active bays <strong>and</strong> one drop-off bay)<br />

as calculated in Table A-7. Bus bay<br />

utilization in Table A-8 may be above<br />

100 percent, but actual utilization at<br />

these bays will likely be much lower<br />

provided that drivers use designated<br />

layover spaces.<br />

Table A-8: Bus Bay Utilization (Year 2040)<br />

Bus<br />

Bay<br />

(S) Buses<br />

per Peak<br />

Hour<br />

(T) Total<br />

Time at Bay<br />

(minutes)<br />

(U) Bay<br />

Utilization<br />

Route<br />

Provider<br />

M2/C12/C14 <strong>Metro</strong>bus A 7 59 98%<br />

F14/TB32 <strong>Metro</strong>bus, TheBus B 6 69 115%<br />

H11/12/13 <strong>Metro</strong>bus C 5 55 92%<br />

36 <strong>Metro</strong>bus D 5 70 117%<br />

39 <strong>Metro</strong>bus E 5 25 42%<br />

34 <strong>Metro</strong>bus F 5 50 83%<br />

Spare/Drop off - G - - -<br />

S. Buses per Peak Hour = ∑ N per bay<br />

T. Total Time at Bay = ∑ (N * (Q + E)) per bay<br />

U. Bay Utilization = T / 60<br />

<strong>Naylor</strong> <strong>Road</strong> <strong>Metro</strong> <strong>Station</strong> <strong>Area</strong> <strong>Access</strong> <strong>and</strong> <strong>Capacity</strong> Study | 82

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!