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Fault Detection and Diagnostics for Rooftop Air Conditioners

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104<br />

T<br />

(2<br />

T<br />

sh,<br />

ratingopening ,<br />

sh,max<br />

opening<br />

Tsh,<br />

ratingopening , 2<br />

− (<br />

) ) ≈ 1 − reserve_capacity<br />

T<br />

sh,max<br />

opening<br />

<strong>and</strong> solving the equation,<br />

T<br />

T<br />

⇒<br />

sh,<br />

rating,<br />

opening<br />

sh,max<br />

opening<br />

constant<br />

C = ,<br />

1- reserve_capacity<br />

= 1−<br />

reserve _ capacity<br />

3. Determine T<br />

sh , static<br />

<strong>and</strong> T<br />

sh, rating,<br />

opening<br />

as described in the last section,<br />

4. Determine Tsh<br />

, max, opening<br />

<strong>and</strong> set the upper boundary <strong>for</strong> ( Tsh, rating<br />

− Tsh,<br />

static)<br />

.<br />

A1.2.5.3 Validation Using Harms’Data<br />

The 5-ton RTU Data collected by Harms (2002) were used to validate the TXV<br />

Model (Number: CBB-I-VE-5-VGA). This TXV is a Sporlan model <strong>and</strong> normally is used<br />

specially <strong>for</strong> heat pumps because it has a check valve inside.<br />

Global Linear Assumption:<br />

guessed that<br />

According to the manufacturers’rating data,<br />

C<br />

( Tsh<br />

,<br />

, rating<br />

− Tsh<br />

static)<br />

= constant = 1.125<br />

From experimental data set A from Harms (2002) with a nominal charge, it can be<br />

o<br />

T sh , rating<br />

= 8<br />

C<br />

Assuming<br />

T<br />

sh<br />

o<br />

, rating,<br />

opening<br />

= 4 C , so<br />

T<br />

sh<br />

, static<br />

= Tsh,<br />

rating<br />

−Tsh,<br />

rating,<br />

opening<br />

= 8 − 4 =<br />

o<br />

4<br />

C<br />

So,<br />

1125<br />

C = .<br />

4<br />

= 0.2813<br />

104

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