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SPECIFICATION FOR THE DESIGN OF - Transcon Steel

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44 Commentary on the Prescriptive Method for One and Two Family Dwellings - 2004<br />

The concentrated loads are calculated as follow:<br />

⎡4⎤<br />

⎡8⎤<br />

P u1 = [ 1.2(10)<br />

+ 1.6(40) ]<br />

⎢<br />

⎣<br />

⎥<br />

x<br />

2⎦<br />

⎢<br />

⎣2⎥ = 608 lb<br />

⎦<br />

P u2 = 630 lb<br />

The maximum moment is calculated to be 5.08 ft-k<br />

M/ΦM T = 5.08/14.165 = 0.36 < 1.0<br />

ok<br />

Note that the above calculation assumes that both trimmer joist sizes and materials are the<br />

same and hence posses similar stiffness. In most residential application this assumption is valid.<br />

However, in cases where trimmer joists materials and/or sizes are different, stiffness<br />

calculations must be done and the appropriate load should be applied to each trimmer joist<br />

component.<br />

D4 Floor Diaphragm Design<br />

Check the adequacy of a 7/16” OSB unblocked floor diaphragm for a 40x60 ft, two-story<br />

building subjected to 110 mph wind speed. The building has a roof slope of 12:12, mean roof<br />

height of 30 ft, and 8’ wall studs at each floor. The building is located in Exposure Category C.<br />

The OSB floor sheathing is fastened to the floor joists with No. 8 screws spaced at 6” o.c. at<br />

panel edges and at 12” o.c. at intermediate supports.<br />

Building<br />

Roof<br />

40’<br />

60’<br />

Force<br />

Direction<br />

40’<br />

Building Width<br />

60’<br />

Building Length<br />

Plan View<br />

From Table C2.1, the following wind pressures are obtained for the given wind speed,<br />

exposure and roof slope:<br />

Roof pressure<br />

Roof corner pressure<br />

Main building pressure<br />

Main building corner pressure<br />

= 11.7 psf<br />

= 14.6 psf<br />

= 24.1 psf<br />

= 30.3 psf<br />

Calculate corner area width (2a), where “a” equals 10% of least width or 0.4h (whichever is<br />

smaller) but not less than either 4% of least width or 3 feet.<br />

a = 10%(40) = 4’<br />

a = 0.4(30) = 12’<br />

a = 3’

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