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SPECIFICATION FOR THE DESIGN OF - Transcon Steel

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82 Commentary on the Prescriptive Method for One and Two Family Dwellings - 2004<br />

C3.1.2.1 Lateral Buckling Strength<br />

M n = S c F c<br />

Φ b = 0.90<br />

(Eq. C3.1.2.1-1)<br />

By calculating the effective section modulus based on mid-span compression flange<br />

bracing, the resulting un-factored nominal moment is:<br />

M n = 12,921 in-lb<br />

(iterative calculation)<br />

C3.1.3 "Beams Having One Flange Through-Fastened to Deck or Sheathing"<br />

Does not apply.<br />

The factored moment is the smallest nominal moment calculated per AISI Specification<br />

Sections C3.1.1, C3.1.2, and C3.1.3 multiplied by the appropriate resistant factor, Φ.<br />

wL<br />

M u = Φ M n = <br />

8<br />

2<br />

L<br />

L = 121.2” L = 10’-2”<br />

F1.5 Shear Capacity<br />

Φ M n<br />

= 8 b<br />

<br />

w<br />

Design shear strength = Φ v V = 744.13 lbs,<br />

L<br />

=<br />

8(0.90)(12,921)<br />

76<br />

12<br />

w = uniform load (plf) = 76 plf<br />

Use the design shear strength to calculate the maximum unsupported span length.<br />

wL 2V<br />

2x744.13<br />

V = L = L = = 19’-7”<br />

2 w<br />

76<br />

F1.6 Deflection Limit<br />

Deflection due to total loads:<br />

δ = 5 4<br />

wL<br />

(simply supported single span deflection equation)<br />

384EI<br />

W = (5 psf + 20 psf)(24”/12”) = 50 plf (service load)<br />

384(29,500,000)(1.4506)<br />

L =<br />

= 12'-5"<br />

3<br />

5(240)(50)<br />

12<br />

Deflection due to live load:<br />

W = (20 psf)(24”/12”) = 40 plf (service load)<br />

384(29,500,000)(1.4506)<br />

L =<br />

= 11'-8"<br />

3<br />

5(360)(40)<br />

12<br />

The resulting joist span is 10’-2”<br />

(controlled by lateral buckling strength)

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