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SPECIFICATION FOR THE DESIGN OF - Transcon Steel

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86 Commentary on the Prescriptive Method for One and Two Family Dwellings - 2004<br />

F2.7 Shear Capacity<br />

Nominal shear strength x Φ v = 1,532 lb (punched section)<br />

w = uniform load (plf) = 86 plf<br />

wL 2V<br />

2x1532<br />

V = L = L = = 35’-7”<br />

2 w<br />

86<br />

F2.8 Deflection Limit<br />

δ = 5 4<br />

wL<br />

384EI = L/180 (simply supported single span deflection equation)<br />

L =<br />

3<br />

384(29,500,000)(4.581)<br />

5(180)(57.7)<br />

12<br />

where, w = (7/cos26.56 psf + 0.7x30 psf)(24”/12”) = 57.7 plf<br />

L= 19’-1"<br />

Bending controls the design, hence the allowable rafter span is L = 16'-8". This is<br />

adequate for the given example.<br />

F3 Ridge Member Shear Connection<br />

Consider the horizontal projection of a simply supported rafter.<br />

V max = wL/2 (L=16 ft, w = 86 plf)<br />

V max = 86 x 16/2 = 688 lb<br />

Screw Shear Capacity (calculated per Section E4.3 of the Specification (AISI, 1999)).<br />

Screw diameter, d = 0.19 inches (# 10 screw, based on AISI Commentary to Specification<br />

Table C-E4-1).<br />

Ultimate capacity of steel = 45 ksi (tensile)<br />

<strong>Steel</strong> design thickness = 0.0451” (43 mils minimum thickness)<br />

Φ = 0.5<br />

t 2 /t 1 ≤ 1.0, The nominal shear strength per screw, P ns , is the smallest of:<br />

3<br />

P ns = 4.2⎜⎛ t2d<br />

⎟⎞<br />

F ⎠<br />

u2<br />

⎝<br />

(Eq. E4.3.1-1)<br />

P ns = 2.7t 1 dF u1<br />

(Eq. E4.3.1-2)<br />

P ns = 2.7t2dF u2<br />

(Eq. E4.3.1-3)<br />

where: t 1 = t 2 = 0.0451” and F u1 = F u2 = 45 ksi<br />

P ns = 789 lbs.

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