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178 2. Tutorial
the equations for the output variable I$VLOAD symbolically yielding an explicit formula describing
the input-output behavior.
In[31]:= eqs = GetEquations[step5];
In[32]:= eqs2 = Eliminate[eqs, {V$3, V$4, V$5}]
Eliminate::ifun:
Inverse functions are being used by Eliminate, so some
solutions may not be found.
Out[32]=
I$VLOAD
Log
AREA$Q4 IS$Q4 ⩵⩵
IB
Log
AREA$Q1 IS$Q1 Log II
I$VLOAD
1. Log
AREA$Q2 IS$Q2 AREA$Q3 IS$Q3
In[33]:= Solve[Map[Exp, eqs2], I$VLOAD]
Out[33]=
1. AREA$Q3 AREA$Q4 IB II IS$Q3 IS$Q4
I$VLOAD
AREA$Q1 AREA$Q2 IS$Q1 ,
IS$Q2
1. AREA$Q3 AREA$Q4 IB II IS$Q3 IS$Q4
I$VLOAD
AREA$Q1 AREA$Q2 IS$Q1
IS$Q2
From the result it can be seen that the output current I$VLOAD depends on the square root of the
input current II and that it is independent of the input voltage VLOAD.