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60 2. Tutorial
In[13]:= darlington =
Circuit[
Netlist[
{I1, {0, 1}, 1},
{Q1, {1 −> "B", 2 −> "C", 3 −> "E"},
Model −> NPNTransistor, Selector −> ACsimple},
{Q2, {3 −> "B", 2 −> "C", 0 −> "E"},
Model −> NPNTransistor, Selector −> ACsimple},
{Load, {0, 2}, Type −> Resistor, Value −> RL,
Pattern −> Impedance}
],
Model[
Name −> NPNTransistor,
Selector −> ACsimple,
Ports −> {"B", "C", "E"},
Parameters −> {RB, beta},
Definition −>
Netlist[
{RB, {"X", "E"}, RB},
{CC, {"B", "X", "C", "E"}, beta}
]
]
]
Out[13]= Circuit
In[14]:= ExpandSubcircuits[darlington] // DisplayForm
Out[14]//DisplayForm=
Netlist Flat, 6 Entries:
I1, 0, 1, 1
RB$Q1, X$Q1, 3, RB$Q1
CC$Q1, 1, X$Q1, 2, 3, beta$Q1
RB$Q2, X$Q2, 0, RB$Q2
CC$Q2, 3, X$Q2, 2, 0, beta$Q2
Load, 0, 2, Type Resistor, Value RL, Pattern Impedance
After having been defined as parameters, the base resistances and current gains appear properly
instantiated in the flat netlist. We can now complete our analysis of the Darlington amplifier by
solving the MNA equations for the load current I$Load.