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Aluminium Design and Construction John Dwight

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where A E =area of the element (normally taken positive), <strong>and</strong> Y E =distance<br />

of the element’s centroid E from XX taken positive above XX <strong>and</strong><br />

negative below.<br />

The summations are performed for all the elements. The correct position<br />

for the neutral axis is obtained, however XX is chosen, provided the<br />

sign of Y E is taken correctly. A negative value of Y G would indicate that<br />

the neutral axis lies below XX. There are then two possible formulae<br />

for I xx which both give the same answer:<br />

Either<br />

or<br />

(10.9)<br />

(10.10)<br />

Expression (10.9) is the one taught to students. Expression (10.10) is<br />

more convenient for complex sections because a small design change to<br />

one element does not invalidate the quantities for all the others.<br />

10.3.2 Inertias for a section with no axis of symmetry<br />

When the section is skew-symmetric or asymmetric (Figure 10.5) we usually<br />

need to know the inertias about the principal axes (Gu, Gv), known as<br />

the principal inertias (Iuu , Ivv ). The procedure for finding the orientation<br />

of the principal axes <strong>and</strong> the corresponding inertias is as follows:<br />

1. Select convenient preliminary axes Gx <strong>and</strong> Gy through the centroid<br />

G, with Gy directed 90° anti-clockwise from Gx.<br />

2. Calculate the inertia lxx . using equation (10.9) or (10.10). Use an<br />

equivalent expression to calculate Iyy .<br />

3. Calculate the product of inertia Ixy (Section 10.3.3).<br />

4. The angle a between the major principal axis Gu <strong>and</strong> the known axis<br />

Gx is then given by:<br />

(10.11)<br />

Figure 10.5 Elastic bending, principal axes.<br />

Copyright 1999 by Taylor & Francis Group. All Rights Reserved.

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