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Building Services Engineering 5th Edition Handbook

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Condensation in buildings 245<br />

where y is the number whose logarithm to base e is x. Logarithms to base e are called natural<br />

logarithms and are expressed as follows:<br />

log e y = x or ln y = x<br />

EXAMPLE 10.3<br />

Compute the natural logarithm of 2 and then raise e to the power of this logarithm.<br />

Enter 2 into the calculator x display and press the ln key; the answer is 0.6931. Therefore:<br />

ln 2 = 0.6931 or log e 2 = 0.6931<br />

Now, as x = 0.6931 is displayed in the calculator, execute e x . This results in<br />

e 0.6931 = 2<br />

Thus it is seen that e x is the antilogarithm of ln x, and the two expressions y = e x and ln y = x<br />

are interchangeable to suit the problem. Thus for:<br />

p s<br />

600.245 = exp(0.0684 t dp )<br />

we can write:<br />

(<br />

ln<br />

p s<br />

600.245<br />

)<br />

= 0.0684 t dp<br />

and,<br />

1<br />

(<br />

t dp =<br />

0.0684 × ln p<br />

) s ◦C<br />

600.245<br />

EXAMPLE 10.4<br />

Calculate the dew-point for saturated air with a vapour pressure of 2000.6 Pa.<br />

t dp = 1 ( ) 2000.6 ◦<br />

0.0684 × ln C<br />

600.245<br />

= 1 × ln 3.33<br />

0.0684<br />

= 17.6 ◦ C<br />

An alternative general equation is stated in BRE Digest 369 for the calculation of vapour<br />

pressure:<br />

p s = 0.6105 × exp<br />

(<br />

17.269 × tdp<br />

237.3 + t dp<br />

)<br />

kPa

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