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Building Services Engineering 5th Edition Handbook

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36 Energy economics<br />

1 kWh = 1 kWh × 3600 s<br />

1h<br />

Therefore,<br />

=<br />

3600 s × 103<br />

10 × 105.5<br />

= 0.0341 therms<br />

1 therm = 1<br />

0.0341 kWh<br />

= 29.3056 kWh<br />

× 103 W<br />

1kW × 1J<br />

1Ws × 1MJ<br />

10 6 J × 1 therm<br />

105.5 MJ<br />

Gross calorific value of a fuel<br />

The total heat energy content of a fuel is known as the gross calorific value (GCV) and is usually<br />

expressed in megajoules per kilogram (MJ/kg).<br />

EXAMPLE 2.2<br />

Heating oil has a specific gravity of 0.84 and a GCV of 44.8 MJ/kg. Find its heat content<br />

in kWh per litre.<br />

GCV = 44.8 MJ 0.84 kg<br />

× × 103 kJ<br />

× 1 kWs × 1h<br />

kg 1l 1MJ 1kJ 3600 s<br />

=<br />

44.8 × 0.84 × 103<br />

3600<br />

= 10.453 kWh/l<br />

kWh/l<br />

EXAMPLE 2.3<br />

A site uses 48 000 l of oil of GCV 44.0 MJ/kg and specific gravity 0.84 costing £22 500<br />

and 2 × 10 6 kWh of electricity costing 7.2 p per kWh. The fixed charge for the electrical<br />

installation is £3500 and the servicing cost for the oil-fired heating system is £8500. The<br />

period of use being considered is 1 year. Draw up an overall energy audit for the year.<br />

oil GCV = 44.0 MJ 0.84 kg<br />

× × 103 kJ<br />

× 1 kWs × 1h<br />

kg 1l 1MJ 1kJ 3600 s<br />

= 10.27 kWh/l<br />

total cost of oil = £22 500 + £8500<br />

= £31 000

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