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Materials for engineering, 3rd Edition - (Malestrom)

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Composite materials 203<br />

fractures be<strong>for</strong>e the fibres and then all the load is transferred to the fibres: the<br />

fibres are unable to support this load and they break, so<br />

σc * = σ f ff + σ m * (1 – f f )<br />

[6.5]<br />

When f f is large, the matrix takes only a small proportion of the load, because<br />

E f > E m , so that when the matrix fractures the fibres do not experience a<br />

sufficient increase in load to cause them to fracture and the load on the<br />

composite can be increased until the fracture stress of the fibres (σ * f ) is<br />

reached, so<br />

σc * = σ f * f f<br />

[6.6]<br />

The fracture strength of the composite varies with f f as illustrated in Fig.<br />

6.12, and this analysis is applicable to glass fibre–polyester resin composites.<br />

If the failure strain of the fibre is less than the failure strain of the matrix<br />

(Fig. 6.13), at low values of f f , when fibre fracture occurs the extra load is<br />

insufficient to fracture the matrix, so<br />

σc * = σ m * ff + σ m * (1 – f f )<br />

[6.7]<br />

When f f is large, however, when fibre fracture occurs, the large extra load<br />

cannot be carried by the matrix and so the matrix fractures (at σ m ) when the<br />

fibres fail, giving:<br />

σ = σ f + σ (1 – f )<br />

[6.8]<br />

c * f * f m f<br />

σ f<br />

*<br />

σc * = σ * f f f<br />

Stress<br />

σc * = σf′ff+ σm * (1– ff)<br />

σ m<br />

*<br />

0 f ’ f f f 1.0<br />

6.12 Variation of fracture stress of composite with volume fraction of<br />

fibres, when ε < ε .<br />

m * f *

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