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Materials for engineering, 3rd Edition - (Malestrom)

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Composite materials 209<br />

(a) (b) (c) (d)<br />

6.19 Propagating transverse crack in an element of fibre composite.<br />

When fracture occurs by the breaking of fibres, then all those fibres which<br />

end within a distance l c /2 of the cross-section which crosses the break will<br />

pull out of the matrix. The fraction pulling out is thus = l c /l. Assuming the<br />

fibre/matrix interfacial shear strength τ is maintained constant, the work to<br />

pull out one fibre of length x is<br />

work = πr<br />

2<br />

∫<br />

0<br />

∫<br />

x<br />

σ dx<br />

2<br />

= πr (2 τx/ r)dx<br />

= πrτx 2<br />

0<br />

x<br />

For a volume fraction of fibres f f , the number of fibres per unit area =<br />

f f /πr 2 . In order to pull out, the fibres can only have a length up to l c /2 above<br />

the plane of fracture: if this distance from the fibre end is x, then the work<br />

of pullout is exactly πrτx 2 . (N.B. if the distance is (x + dx), the work is still<br />

the same, since dx is vanishingly small).<br />

Considering all the possible positions along the fibre where the plane of<br />

fracture might be, the probability of it intersecting exactly at x is zero, but the<br />

probability of it intersecting over the length dx (i.e. of pulling out a length<br />

between x and x + dx must be:<br />

d x/total length = d x/ 1 l<br />

2 c<br />

So the total work of pullout is,<br />

l0<br />

/2<br />

2<br />

2<br />

W = ( f / πr ) l / l πrτx d x/( l /2)<br />

f<br />

ffτlc 3<br />

= 12 rl<br />

c<br />

∫<br />

0<br />

c

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