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Protocol for the Derivation of Environmental and Human ... - CCME

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Appendix C<br />

<strong>Derivation</strong> <strong>of</strong> <strong>the</strong> Partitioning Relationship <strong>for</strong> Protection <strong>of</strong><br />

Groundwater<br />

Numerous studies have shown that sorption <strong>of</strong> organics by soils is highly correlated with <strong>the</strong> organic<br />

matter content (e.g., Chiou et al. 1979, Hassett et al. 1980). Chiou (1989) presents evidence that <strong>the</strong><br />

linearity <strong>of</strong> sorption with organic contaminant concentration <strong>and</strong> correlation with soil organic matter<br />

content reflect dissolution <strong>of</strong> <strong>the</strong> organic contaminant into <strong>the</strong> soil organic matter phase -- as opposed to<br />

sorption to organic matter surfaces. Normally a Freundlich iso<strong>the</strong>rm is fitted to <strong>the</strong> sorption data:<br />

Cs = K d × C w<br />

1/n<br />

[1]<br />

where<br />

C s = concentration in solid phase (mg/kg)<br />

K d = distribution coefficient<br />

C w = concentration in aqueous phase (mg/L)<br />

n = empirical constant<br />

For most non-ionic organics n=1 <strong>and</strong> sorption is a linear function <strong>of</strong> equilibrium solution concentration<br />

up to 60% to 80% <strong>of</strong> its water solubility (Hassett <strong>and</strong> Banwart 1989). The relationship between solution<br />

concentrations <strong>and</strong> <strong>the</strong> sorbed concentration is described in equation 1. The relationship between total<br />

soil concentration <strong>and</strong> soil solution concentration can be derived using a simple method based only on<br />

mass ratio <strong>of</strong> water over soil considerations.<br />

Consider a unit dry mass <strong>of</strong> soil, M s , at field capacity moisture content ? m defined by<br />

? m = M w /M s [2]<br />

where<br />

M w = mass <strong>of</strong> water<br />

M s = dry mass <strong>of</strong> soil<br />

The soil is contaminated by a chemical to a concentration Y (mg kg -1 dry mass basis) <strong>and</strong> <strong>the</strong> chemical<br />

is partitioned between solid <strong>and</strong> aqueous phases <strong>of</strong> <strong>the</strong> moist soil per:<br />

By mass balance we have:<br />

K d = C s /C w [3]<br />

Y × M s = (C s × M s ) + (C w × M w ) [4]<br />

139

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