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Single-Particle Electrodynamics - Assassination Science

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Now, the torque on an object (around its centre of energy) is simply the<br />

time rate of change of its mechanical spin angular momentum,<br />

N ≡ ṡ,<br />

in the same way that the force is the time rate of change of its linear mechanical<br />

momentum,<br />

F ≡ ṗ.<br />

In general, the spin angular momentum s of a classical object may be of any<br />

value, and point in any direction. In particular, there is no good reason why<br />

it should point in the same direction as the electric dipole moment: it can<br />

do so (e.g., if one uses the rigid stick above as an axis for a rotating flywheel,<br />

and one assumes the charges and the rigid stick to be themselves massless);<br />

but it need not, in general.<br />

On the other hand, we shall often wish to apply the equations of motion<br />

derived in this thesis to the case of a spin-half particle, such as an electron.<br />

For such a particle, we know that the mass must be a constant of the motion<br />

(namely, m e ); and we know that the magnitude s of its spin angular momentum<br />

must be a constant of the motion (namely, 2¯h). But we also know that<br />

1<br />

any dipole moment of a spin-half particle must be parallel to its spin vector<br />

s (basically because there are no other three-vectors available in the Dirac<br />

algebra):<br />

d ≡ dσ,<br />

s ≡ sσ ≡ 2¯hσ. 1<br />

With such a parallelism identity in effect, we may use the torque result N<br />

to obtain the precession rate very simply:<br />

d˙ ∣ = d<br />

d‖s sṡ ≡ d N. (4.12)<br />

s<br />

123

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