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Single-Particle Electrodynamics - Assassination Science

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the force on the electric-current magnetic dipole. But there is again a twist;<br />

we shall return to this shortly.<br />

We now turn to the question of the torque on an electric-current magnetic<br />

dipole.<br />

Fortunately, this problem is not subject to any controversy<br />

whatsoever. In this nonrelativistic analysis, we simply sum the “momentarm”<br />

torques on all of the circulating constituent charges:<br />

N = n ∫ 2π<br />

dθ { N<br />

2π<br />

+<br />

(θ) + N −<br />

(θ) } . (4.40)<br />

0<br />

Since each torque is only dependent on the force at that position θ, we can<br />

immediately make use of the sum of the torques on the positive and negative<br />

charges at that position:<br />

From (4.36), we find<br />

N(θ) ≡ N +<br />

(θ) + N −<br />

(θ) ≡ z(θ)×F (θ).<br />

N(θ) = 2qz(θ)× ( v +<br />

(θ)×B(θ) ) ;<br />

using the identity<br />

and noting that<br />

a×(b×c) ≡ (a·c)b − (a·b)c,<br />

z(θ)·v +<br />

(θ) ≡ 0<br />

(since the charge is moving in circular motion, i.e., with velocity perpendicular<br />

to its radius vector), we thus find<br />

N(θ) = 2q ( z(θ)·B(θ) ) v +<br />

(θ). (4.41)<br />

Substituting (4.41) into (4.40), using (4.22), (4.27) and (4.29), and integrating,<br />

we find<br />

{ }<br />

N = nqεv orb −i By + jB x + O(ε 2 ). (4.42)<br />

137

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