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Single-Particle Electrodynamics - Assassination Science

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(often counter-intuitive) complications involved when the system is moving<br />

with an arbitrarily relativistic speed. One therefore often decides to analyse<br />

the system in question in the nonrelativistic limit; and then, after the correct<br />

physics has been ascertained, kinematically “extrapolate” the results to the<br />

relativistic domain.<br />

Such a procedure sounds simple enough. It is, however, a potential minefield.<br />

In this section, we will describe the steps that need to be taken to<br />

ensure that one is not led down an incorrect path; on the other hand, it is<br />

shown that, with suitable care, the process is not as difficult as sometimes<br />

imagined.<br />

Firstly, it must be noted that Galilean kinematics and Lorentzian kinematics<br />

do not fit together as well as one might at first think. On the surface<br />

of it, it may appear that the former is the “first approximation” of the latter:<br />

Galilean expressions appear to be correct up to first order in a particle’s velocity,<br />

v, but not to second order. For example, the mechanical momentum<br />

of a point particle is given, in Galilean kinematics, by<br />

p = mv,<br />

whereas in relativistic kinematics it is given by<br />

p = √ mv = mv + 1 1 − v<br />

2 2 mv2 v + · · · .<br />

But the first-order-in-v rule is often incorrect. Consider a dumbbell model<br />

of an electric dipole: two charges on the ends of a stick. Call their relative<br />

displacement ∆l. Relativistically, this relative displacement is actually the<br />

three-vector part of a four-vector, ∆L α , which has vanishing zero-component<br />

in the object’s rest frame. If this object is boosted by a velocity v, then the<br />

Lorentz transformation (G.1) shows that, to first order in v, the components<br />

of the four-vector ∆L are transformed into<br />

∆L 0 = (v·∆l) + O(v 2 ),<br />

∆L = ∆l + O(v 2 ). (2.81)<br />

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