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Single-Particle Electrodynamics - Assassination Science

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σ µν is antisymmetric. The six remaining terms, F i and H i (i = 1, 2, 4), are<br />

further constrained by the requirement of conservation of the fermion current,<br />

(k·J) = 0. Since<br />

u 2 k/u 1 ≡ u 2 b/ 2 u 1 − u 2 b/ 1 u 1 = 0<br />

by the Dirac equation, as does (k·σ·k) by symmetry, this requirement has<br />

no effect on the terms F 1 , F 4 and H 4 . However, since k 2 ≠ 0 in general, the<br />

remaining terms must satisfy<br />

u 2<br />

(<br />

F2 k 2 + H 1 k/γ 5 + H 2 k 2 γ 5<br />

)<br />

u1 = 0.<br />

(E.3)<br />

Now, we can transform the H 1 term by use of the Dirac equation for the<br />

incoming and outgoing fermion states, from which one can verify the identity<br />

u 2 k/γ 5 u 1 ≡ 2m u 2 γ 5 u 1 . For the requirement (E.3) to hold in general, we<br />

therefore require F 2 = 0 and 2mH 1 + k 2 H 2 = 0. Replacing H 1 using this<br />

result, defining a(k 2 ) ≡ H 2 (k 2 )/2m, and replacing the u 2 γ 5 u 1 in the H 2 term<br />

by u 2 k/γ 5 u 1 /2m, the general interaction vertex can then be written<br />

{<br />

(J ·A) = u 2 F1 (k 2 )γ µ + F 4 (k 2 )σ µν k ν + H 4 (k 2 )σ µν k ν γ 5<br />

+ a(k 2 ) ( k/k µ − k 2 γ µ) }<br />

γ 5 u1 A µ . (E.4)<br />

E.3 The classical limit<br />

We now investigate what interaction Lagrangian will be obtained from the<br />

vertex (E.4) in the classical limit.<br />

As we are, in this limit, treating the<br />

fermion as a particle, but the photon as a field, it is appropriate to return<br />

to position space and replace the photon canonical momentum, k, by the<br />

partial derivative of the external potentials and fields, ∂. At the same time,<br />

we must replace the various matrix elements in (E.4) by some sort of classical<br />

counterparts.<br />

desired results:<br />

It is found that the following transformations produce the<br />

u 2 γ µ u 1 −→ U µ + 1<br />

2m ˜Σ µν ∂ ν ,<br />

391

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