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Single-Particle Electrodynamics - Assassination Science

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exercise will be of use in guiding us in future sections. We know that, for<br />

the purpose of computing a charged point particle’s equations of motion, the<br />

electric charge interaction Lagrangian is<br />

L int = qU α A α . (5.3)<br />

We can turn this Lagrangian into a Lagrangian density by converting the<br />

point particle’s electromagnetic current, qU α , into a current density, J α (x),<br />

via<br />

∫<br />

J α (x) ≡ dτ qU α (τ) δ (4) [x − z(τ)] . (5.4)<br />

Then (5.3) is equivalent to the Lagrangian density<br />

L int = J α A α , (5.5)<br />

and so the complete Lagrangian density, as far as the electromagnetic field<br />

is concerned, is simply the sum of (5.1) and (5.5):<br />

L = L free + L int = 1 4 F αβ F αβ + J α A α . (5.6)<br />

5.3.2 The Maxwell equation<br />

A straightforward application of the field Euler–Lagrange equations to the<br />

Lagrangian density (5.6) yields the familiar (inhomogeneous) Maxwell equation,<br />

equation (B.7) of Section B.2.7:<br />

∂ µ F µν = J ν . (5.7)<br />

5.3.3 Solution of the Maxwell equation<br />

One’s next task is to determine the solution of (5.7) for some given electric<br />

current distribution J ν (x). While it is possible to obtain this information<br />

directly from (5.7), it is simpler to employ again the four-potential A µ , purely<br />

179

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