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Producer Price Index Manual: Theory and Practice ... - METAC

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18. Aggregation Issues<br />

(18.4) R 0 (p 0 ,v 0 ) =<br />

<strong>and</strong> R 1 (p 1 ,v 1 ) =<br />

E<br />

N<br />

∑∑<br />

e= 1 n=<br />

1<br />

p q<br />

e0 e0<br />

n n<br />

E N<br />

e1 e1<br />

∑∑ pn<br />

qn<br />

.<br />

e= 1 n=<br />

1<br />

Under these revenue maximizing assumptions,<br />

adapting the arguments of F. M. Fisher <strong>and</strong> Shell<br />

(1972, pp. 57–58) <strong>and</strong> Archibald (1977, p. 66),<br />

Diewert (2001) showed that the two theoretical indices,<br />

P 0 (p 0 ,p 1 ,v 0 ) <strong>and</strong> P 1 (p 0 ,p 1 ,v 1 ), described in (i)<br />

<strong>and</strong> (ii) above, satisfy the following inequalities of<br />

equations (18.5) <strong>and</strong> (18.6):<br />

(18.5) P 0 (p 0 ,p 1 ,v 0 ) R 0 ( p 1 , v 0 ) R 0 ( p 0 , v<br />

0<br />

)<br />

using equation (18.3)<br />

using equation (18.4)<br />

≡ ,<br />

E N<br />

= ( , ) ∑∑<br />

R p v p q<br />

0 1 0 e 0 e 0<br />

n n<br />

e= 1 n=<br />

1<br />

E N E N<br />

e1 e0 e0 e0<br />

pn qn pn qn<br />

e= 1 n= 1 e= 1 n=<br />

1<br />

≥ ∑∑ ∑∑<br />

since q e0 is feasible for the maximization problem<br />

that defines R e0 (p e1 ,v e0 ), <strong>and</strong> so<br />

( , )<br />

N<br />

e 0 e 1 e 0 e 1 e 0<br />

n n<br />

n=<br />

1<br />

R p v ≥ ∑ p q for e = 1,...,E<br />

≡ P L (p 0 ,p 1 ,q 0 ,q 1 ),<br />

where P L is the Laspeyres output price index,<br />

which treats each commodity produced by each establishment<br />

as a separate commodity. Similarly,:<br />

(18.6) P 1 (p 0 ,p 1 ,v 1 ) ≡ R 1 ( p 1 , v 1 ) R 1 ( p 0 , v<br />

1<br />

)<br />

using equation (18.3)<br />

using equation (18.4)<br />

E<br />

N<br />

= ∑∑<br />

e= 1 n=<br />

1<br />

( , )<br />

p q R p v<br />

e 1 e 1 1 0 1<br />

n n<br />

E N E N<br />

e1 e1 e0 e1<br />

pn qn pn qn<br />

e= 1 n= 1 e= 1 n=<br />

1<br />

≤ ∑∑ ∑∑<br />

since q e1 is feasible for the maximization problem<br />

that defines R e1 (p e0 ,v e1 ),<strong>and</strong> so<br />

( , )<br />

N<br />

e 1 e 0 e 1 e 0 e 1<br />

n n<br />

n=<br />

1<br />

R p v ≥ ∑ p q for e = 1,...,E<br />

≡ P P (p 0 ,p 1 ,q 0 ,q 1 ),<br />

where P P is the Paasche output price index, which<br />

treats each commodity produced by each establishment<br />

as a separate commodity. Thus, equation<br />

(18.5) says that the observable Laspeyres index of<br />

output prices P L is a lower bound to the theoretical<br />

national output price index P 0 (p 0 ,p 1 ,v 0 ) <strong>and</strong> equation<br />

(18.6) says that the observable Paasche index<br />

of output prices P P is an upper bound to the theoretical<br />

national output price index P 1 (p 0 ,p 1 ,v 1 ).<br />

18.9 It is possible to relate the Laspeyres-type<br />

national output price index P 0 (p 0 ,p 1 ,v 0 ) to the individual<br />

establishment Laspeyres-type output price<br />

indices P e0 (p e0 ,p e1 ,v e0 ), defined as follows:<br />

(18.7) P e0 (p e0 ,p e1 ,v e0 )<br />

≡ R p , v R p , v<br />

for e = 1,...,E<br />

( ) ( )<br />

e0 e1 e0 e0 e0 e0<br />

( , )<br />

e 0 e 1 e 0 N<br />

e 0 e<br />

∑<br />

0<br />

n n<br />

n=<br />

1<br />

= R p v p q ≥<br />

where the establishment period 0 technology revenue<br />

functions R e0 were defined above by equation<br />

(18.1) <strong>and</strong> assumptions in equation (18.4) were<br />

used to establish the second set of equalities; that<br />

is, the assumption that each establishment’s observed<br />

period 0 revenues,<br />

N<br />

∑<br />

n=<br />

1<br />

p q<br />

e0 e0<br />

n n<br />

, are equal to<br />

the optimal revenues, R e0 (p e0 ,v e0 ). Now define the<br />

revenue share of establishment e in national revenue<br />

for period 0 as<br />

(18.8) S e<br />

0<br />

N E N<br />

e0 e0 e0 e0<br />

pn qn pn qn<br />

n= 1 e= 1 n=<br />

1<br />

≡ ∑ ∑∑ ; e = 1,...,E.<br />

Using the definition of the Laspeyres type national<br />

output price index P 0 (p 0 ,p 1 ,v 0 ), equation (18.3), for<br />

(t,v) = (0,v 0 ), <strong>and</strong> using also equation (18.2):<br />

(18.9) P 0 (p 0 ,p 1 ,v 0 )<br />

E<br />

0 ( 1 0 E<br />

e e e e<br />

, ) 0 e<br />

( 0 e<br />

≡ ∑R p v ∑ R p , v<br />

0<br />

)<br />

e= 1 e=<br />

1<br />

E<br />

e=<br />

1<br />

( ,<br />

⎝<br />

) E<br />

∑<br />

= ∑ R p v<br />

e0 e0 e0<br />

e=<br />

1<br />

( , )<br />

( , )<br />

⎛ R p v<br />

⎜R p v<br />

e0 e1 e0<br />

e0 e0 e0<br />

( , )<br />

R p v<br />

e0 e0 e0<br />

⎞<br />

⎟<br />

⎠<br />

465

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