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Radiography in Modern Industry - Kodak

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Example: Suppose that with a given exposure time and kilovoltage, a properly exposedradiograph is obta<strong>in</strong>ed with 5mA (M 1 ) at a distance of 12 <strong>in</strong>ches (D 1 ), and that it is desired to<strong>in</strong>crease the sharpness of detail <strong>in</strong> the image by <strong>in</strong>creas<strong>in</strong>g the focus-film distance to 24 <strong>in</strong>ches(D 2 ). The correct milliamperage (M 2 ) to obta<strong>in</strong> the desired radiographic density at the <strong>in</strong>creaseddistance (D 2 ) may be computed from the proportion:When very low kilovoltages, say 20 kV or less, are used, the x-ray <strong>in</strong>tensity decreases withdistance more rapidly than calculations based on the <strong>in</strong>verse square law would <strong>in</strong>dicate becauseof absorption of the x-rays by the air. Most <strong>in</strong>dustrial radiography, however, is done with radiationso penetrat<strong>in</strong>g that the air absorption need not be considered. These comments also apply to thetime-distance relations discussed below.Time-Distance RelationRule: The exposure time (T) required for a given exposure is directly proportional to the square ofthe focus-film distance (D). Thus:To solve for either a new Time (T 2 ) Or a new Distance (D 2 ), simply follow the steps shown <strong>in</strong> theexample above.Tabular Solution of Milliamperage-Time and Distance ProblemsProblems of the types discussed above may also be solved by the use of a table similar to TableV. The factor between the new and the old exposure time, milliamperage, or milliamperagem<strong>in</strong>ute(mA-m<strong>in</strong>) value appears <strong>in</strong> the box at the <strong>in</strong>tersection of the column for the new sourcefilmdistance and the row for the old source-film distance.Suppose, for example, a properly exposed radiograph has an exposure of 20 mA-m<strong>in</strong> with asource-film distance of 30 <strong>in</strong>ches and you want to <strong>in</strong>crease the source-film distance to 45 <strong>in</strong>ches<strong>in</strong> order to decrease the geometric unsharpness <strong>in</strong> the radiograph. The factor appear<strong>in</strong>g <strong>in</strong> thebox at the <strong>in</strong>tersection of the column for 45 <strong>in</strong>ches (new source-film distance) and the row for 30<strong>in</strong>ches (old source-film distance) is 2.3. Multiply the old milliampere-m<strong>in</strong>ute value (20) by 2.3 togive the new value--46 mA-m<strong>in</strong>.Note that some approximation is <strong>in</strong>volved <strong>in</strong> the use of such a table, s<strong>in</strong>ce the values <strong>in</strong> the boxesare rounded off to two significant figures. However, the errors <strong>in</strong>volved are always less than 5percent and, <strong>in</strong> general, are <strong>in</strong>significant <strong>in</strong> actual practice.Further, a table like Table V obviously cannot <strong>in</strong>clude all source-film distances, because oflimitations of space. However, <strong>in</strong> any one radiographic department, only a few source-filmdistances are used <strong>in</strong> the great bulk of the work, and a table of reasonable size can beconstructed <strong>in</strong>volv<strong>in</strong>g only these few distances.Milliamperage-Time RelationRule: The milliamperage (M) required for a given exposure is <strong>in</strong>versely proportional to the time(T):Another way of express<strong>in</strong>g this is to say that for a given set of conditions (voltage, distance, etc),the product of milliamperage and time is constant for the same photographic effect.<strong>Radiography</strong> <strong>in</strong> <strong>Modern</strong> <strong>Industry</strong> 61

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