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Radiography in Modern Industry - Kodak

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The problem of radiograph<strong>in</strong>g a part hav<strong>in</strong>g several thicknesses is one of us<strong>in</strong>g the availabledensity range most efficiently. In other words, the kilovoltage and exposure should be adjusted sothat the image of the th<strong>in</strong>nest part has the maximum acceptable density, and the thickest has them<strong>in</strong>imum. Exposure charts alone, although adequate for the radiography of uniform plates, canserve only as rough guides for articles hav<strong>in</strong>g considerable variation <strong>in</strong> thickness. Previousexperience is a guide, but even when a usable radiograph has been obta<strong>in</strong>ed, the questionrema<strong>in</strong>s as to whether or not it is the best that could be achieved.A quantitative method for f<strong>in</strong>d<strong>in</strong>g such exposures comb<strong>in</strong>es <strong>in</strong>formation derived from theexposure chart and the characteristic curve of the film used. The procedure is outl<strong>in</strong>ed below:Assume that 1.0 is the lowest acceptable density on Film X (See Figure 47) and that 3.5 is thehighest. As shown <strong>in</strong> the figure below, this density <strong>in</strong>terval corresponds to a certa<strong>in</strong> log exposure<strong>in</strong>terval, <strong>in</strong> this case 0.63.Figure 60: Characteristic curve of Film X. Dotted l<strong>in</strong>es show how the log E <strong>in</strong>tervalcorrespond<strong>in</strong>g to a certa<strong>in</strong> density <strong>in</strong>terval (<strong>in</strong> this case 1.0 to 3.5) can be found.The antilog of 0.63 is 4.3, which means that 4.3 times more exposure is required to produce adensity of 3.5 than of 1.0. It is therefore desired that the th<strong>in</strong>nest portion of the object to beradiographed transmit exactly 4.3 times more radiation than the thickest part, so that with theproper adjustment of radiographic exposure, all parts of the object will be rendered with<strong>in</strong> thedensity range 1.0 to 3.5. The ratios of x-ray <strong>in</strong>tensities transmitted by different portions of theobject will depend on kilovoltage; exam<strong>in</strong>ation of the exposure chart of the x-ray mach<strong>in</strong>e revealsthe proper choice of kilovoltage. For example, <strong>in</strong> the chart shown <strong>in</strong> the figure below, the 180 kVl<strong>in</strong>e shows that a thickness range of about 7/8 to about 11/4 <strong>in</strong>ches of steel corresponds to anexposure ratio of 35 mA-m<strong>in</strong> to 8 mA-m<strong>in</strong>, or 4.3, which is the ratio required. The next problem isto determ<strong>in</strong>e the radiographic exposure needed. The chart shown below gives the exposure toproduce a density of 1.0 on Film X. S<strong>in</strong>ce it is desired to produce a density 1.0 under the thicksection (11/4 <strong>in</strong>ches), the exposure time would be 35 mA-m<strong>in</strong>.<strong>Radiography</strong> <strong>in</strong> <strong>Modern</strong> <strong>Industry</strong> 83

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