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Gravity and Strings

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2.4 The special-relativistic energy–momentum tensor 35<br />

again, up to terms that vanish on-shell. The second term in this expression can be eliminated<br />

by the usual procedure. The spin-angular-momentum tensor has been absorbed into the<br />

new angular-momentum tensor. We are left with the following conserved on-shell currents<br />

associated with translations <strong>and</strong> Lorentz rotations, both of them expressed in terms of the<br />

same energy–momentum tensor (the Belinfante tensor):<br />

jN1 (ν) µ = T µ ρ ˜δ(ν)x ρ = T µ ρ,<br />

jN1 (ρσ ) µ = T µ λ ˜δ(ρσ )x λ = 2T µ [ρxσ ].<br />

(2.54)<br />

It is worth stressing that the existence of these conserved currents is primarily due to the<br />

invariance of the Minkowski metric that enters into special-relativistic Lagrangians <strong>and</strong> of<br />

the Minkowski volume element under the Poincarégroup or, in other words, to the existence<br />

of d(d + 1)/2 Killing vectors precisely of the form<br />

˜δ(ν)x µ ∂µ = ∂ν, ˜δ(ρσ )x µ ∂µ =−2x[ρ∂σ ]. (2.55)<br />

Acouple of simple examples of the symmetrization of the canonical energy–momentum<br />

tensor are in order here.<br />

The energy–momentum tensor of a vector field. The Lagrangian <strong>and</strong> canonical energy–<br />

momentum tensor are given by<br />

L =− 1<br />

4 F 2 , Fµν = 2∂[µ Aν], Tcan µ ν = F µρ ∂ν Aρ − 1<br />

4ηµ ν F 2 . (2.56)<br />

Under Lorentz rotations we have<br />

˜δ Aµ =−Aνσ ν µ ⇒ S µ ρσ = F µ [ρ Aσ ] ⇒ ρµ ν = F ρµ Aν, (2.57)<br />

<strong>and</strong>, using the equations of motion ∂ρ F ρµ = 0,<br />

T µ ν = Tcan µ ν + ∂ρ ρµ ν = F µρ Fνρ − 1<br />

4ηµ ν F 2 , (2.58)<br />

which is the st<strong>and</strong>ard, gauge-invariant, energy–momentum tensor of a vector field, coinciding<br />

with the one derived via Rosenfeld’s prescription, which we are going to introduce in<br />

Section 2.4.3, inspired by general relativity.<br />

There is yet another way to obtain this energy–momentum tensor that is worth pointing<br />

out: let us consider the transformations<br />

˜δx µ = ɛ µ , ˜δ Aµ = ɛ λ ∂λ Aµ − Lɛ Aµ =−∂µɛ λ Aλ. (2.59)<br />

Following the same steps as those we followed to prove the Noether theorem, we find<br />

now<br />

<br />

˜δS = d d x∂µɛ λ T µ ν, (2.60)<br />

with T µ ν as above (the Belinfante tensor). This variation vanishes if<br />

∂(µɛλ) = 0, (2.61)

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