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Gravity and Strings

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10.3 Sources: the AS shock wave 289<br />

In Chapter 3, Section 3.2.3, we found precisely the same equation <strong>and</strong> it has the same<br />

solution, Eqs. (3.133) <strong>and</strong> (3.134). Thus, we have found the solution<br />

K (u, xd−2) =<br />

ds 2 = 2dudv + 2K (u, xd−2)du 2 − d x 2<br />

√ 2 p8πG (d)<br />

N<br />

(d − 4)ω(d−3)<br />

1<br />

d−2 ,<br />

δ(u), d ≥ 5,<br />

|xd−2|<br />

d−4<br />

K (u, x2) =− √ 2 p4G (4)<br />

N ln |x2| δ(u), d = 4.<br />

(10.39)<br />

The d = 4 solution is the AS shock wave found in [24]. Observe that this solution is exactly<br />

the same as that which we obtained in Section 3.2.3 by solving the linear-order theory.<br />

There are no higher-order corrections to the first-order solution which is not renormalized.<br />

This is due to the special structure of the linear solution <strong>and</strong> can be related to supersymmetry<br />

as well.<br />

There is another useful way to rewrite the pp-wave metrics that we have found. Defining<br />

the function<br />

H ≡ 1 − K, (10.40)<br />

the solution takes the form<br />

ds2 = H −1dt2 − H dz − α(H −1 − 1)dt 2 2 − d x d−2 , α =±1,<br />

√ (d) <br />

2 p8πG N 1 1√2<br />

H = 1 −<br />

δ (t − αz) , d ≥ 5,<br />

(d − 4)ω(d−3) |xd−2|<br />

d−4<br />

H = 1 + √ 2 p4G (4)<br />

N ln |x2|<br />

<br />

1√2<br />

δ (t − αz) , d = 4,<br />

(10.41)<br />

where we have introduced the constant α =±1totake care of the two possible directions<br />

of propagation toward z = α∞.<br />

Had we tried to solve the vacuum Einstein equations with the Ansatz Eq. (10.35), we<br />

would have arrived at the conclusion that any function K (or H) harmonic in (d − 2)dimensional<br />

Euclidean space transverse to z provides a solution. Thus, we obtain a family<br />

of pp-wave solutions of the form<br />

ds2 = H −1dt2 − H[dz − α(H −1 − 1)dt] 2 − d x 2<br />

d−2 ,<br />

∂ 2<br />

(d−2) H = 0, α =±1.<br />

(10.42)

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