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Gravity and Strings

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224 The Reissner–Nordström black hole<br />

If the particle is at rest at the origin in the chosen coordinate system, the current is<br />

j µ (x 0 , x) =−qcδ µ0 δ(3) (x)<br />

√ |g| , (8.51)<br />

<strong>and</strong> it is easy to see that q is indeed the electric charge according to the above definitions.<br />

j µ is a conserved current:<br />

∇µ j µ ∼ ∂<br />

∂x µ<br />

<br />

|g(x)|<br />

<br />

dξ ˙X µ 1<br />

√ δ<br />

|g(X)| (4) <br />

[x − X (ξ)]<br />

<br />

= dξ ˙X<br />

µ ∂<br />

∂x µ δ(4) <br />

[x − X (ξ)] =− dξ ˙X<br />

µ ∂<br />

∂ X µ δ(4) [x − X (ξ)]<br />

<br />

=− dξ d<br />

dξ δ(4) [x − X (ξ)] =−δ (4) [x − X (ξ)] ξ2 = 0, (8.52)<br />

ξ1<br />

generically, except for the initial <strong>and</strong> final positions of the particle X µ (ξ1) <strong>and</strong> X µ (ξ2),<br />

which look like a 1-particle source <strong>and</strong> a sink <strong>and</strong> can be taken to infinity.<br />

Observe that, for the current (8.49), the interaction term (8.40) becomes the integral of<br />

the 1-form A over the worldline γ:<br />

− q<br />

<br />

c<br />

γ(ξ)<br />

Aµ ˙x µ dξ =− q<br />

<br />

A. (8.53)<br />

c γ<br />

This term has to be added to the action of the particle, Eq. (3.255), (3.257) or (3.258), in<br />

order to obtain the worldline action of a massive electrically charged particle,<br />

S[X µ <br />

(ξ)] =−Mc<br />

S 2 ∞<br />

dξ<br />

<br />

gµν(X) ˙X µ ˙X ν − q<br />

<br />

c<br />

dξ Aµ ˙X µ , (8.54)<br />

or that of a massless one. That kind of term is known as a Wess–Zumino (WZ) term. In<br />

this form it is easy to see that, under a gauge transformation, the action changes by a total<br />

derivative. The integral of the total derivative vanishes exactly only for special boundary<br />

conditions, though.<br />

This action can be used as a source, but it also describes the motion of a charged particle<br />

in a gravitational/electromagnetic background. In the special-relativistic limit, taking ξ =<br />

X 0 = ct, the action takes the st<strong>and</strong>ard form<br />

<br />

S ∼ dt −Mc 2 + 1<br />

2 Mv2 − qφ + q<br />

c A<br />

<br />

· v . (8.55)<br />

If there is a point-like charge q at rest at the origin the only non-vanishing components<br />

of F are F0r <strong>and</strong> they should depend only on r because of the spherical symmetry of<br />

the problem. Using the above definition of charge <strong>and</strong> working in general static spherical<br />

coordinates Eq. (7.22), we find<br />

<br />

ɛµνρσ<br />

q =<br />

4 √ |g| F ρσ dx µ ∧ dx ν <br />

= d 2 r 2 2<br />

F0r = ω(2) lim r F0r , (8.56)<br />

r→∞<br />

S 2 ∞

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