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Gravity and Strings

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3.2 <strong>Gravity</strong> as a self-consistent massless spin-2 SRFT 91<br />

The correction to the action with the property (3.230) is precisely<br />

S (2) = 1<br />

χ 2<br />

<br />

d d x −2χϕ αβ Ɣλ[α ρ Ɣρ]β λ . (3.234)<br />

One could naively think that, with this correction, we can obtain only the first term (that<br />

quadratic in Ɣµν ρ )inταβ.However, we have to take into account that the equation for Ɣµν ρ<br />

changes <strong>and</strong>, hence, substituting its solution into the equation for ϕ µν will give us all the<br />

terms we need. Observe also that this correction is cubic in fields whereas the action we<br />

started from is quadratic. Finally, observe that this term will not contribute to the energy–<br />

momentum tensor: there are no Minkowski metrics here to be replaced by the background<br />

metric <strong>and</strong> there is no need to introduce √ |γ | because ϕ µν is, by hypothesis, a tensor<br />

density. Thus, if this term really works, we will not need to introduce any more corrections.<br />

For the total action<br />

S (1) + S (2) = 1<br />

χ 2<br />

<br />

we find the following equations of motion:<br />

χ δ(S(1) + S (2) )<br />

δϕ µν<br />

χ 2 (δS(1) + S (2) )<br />

δƔµν ρ<br />

d d x −χϕ µν 2∂[µƔρ]ν ρ + (η µν − χϕ µν )2Ɣλ[µ ρ Ɣρ]ν λ , (3.235)<br />

=−Rµν(Ɣ) = 0,<br />

= 2Ɣρ (µν) − η µν Ɣρλ λ −η λσ Ɣλσ (µ η ν) ρ − χ∂ρϕ µν + χηρ (µ ∂σ ϕ ν)σ<br />

− 2χϕ δ(µ Ɣρδ ν) + χϕ µν Ɣρσ σ + χϕ λσ Ɣλσ (µ η ν) ρ = 0,<br />

(3.236)<br />

where Rµν(Ɣ) is nothing but the Ricci tensor associated with the connection Ɣµν ρ given in<br />

Eq. (1.33). By defining<br />

g µν = η µν − χϕ µν<br />

(3.237)<br />

<strong>and</strong> its inverse g µρ gρν = g µ ν = δ µ ν, which we are going to use as a metric to raise <strong>and</strong><br />

lower indices, we can write<br />

χ 2 (δS(1) + S (2) )<br />

δƔµν ρ<br />

= 2g δ(µ Ɣρδ ν) − g µν Ɣρδ δ − g λσ Ɣλσ (µ g ν) ρ + ∂ρg µν − gρ (µ ∂σ g ν)σ = 0.<br />

(3.238)<br />

Now we proceed as before: we contract this equation of motion with gµ ρ ,giving<br />

<strong>and</strong> then contract with gµν, using the last equation, giving<br />

Ɣλ λν =−∂σ g σν , (3.239)<br />

Ɣρλ λ = 1<br />

d − 2 gµν∂ρg µν = 1<br />

d − 2 ∂ρ ln |g|, |g|≡det g µν . (3.240)

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