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Gravity and Strings

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584 String black holes in four <strong>and</strong> five dimensions<br />

The mass formula should be compared with that of the extreme BH Eq. (20.27): branes<br />

<strong>and</strong> antibranes contribute equally to it, <strong>and</strong> there seems to be no interaction/binding energy<br />

between them.<br />

The entropy takes the form<br />

√ND5 S = 2π − √ND1 ¯ND5 − √NW ¯ND1 − <br />

¯NW . (20.35)<br />

d = 4 Black holes from intersecting branes. In [549] a stringy model based on a system of<br />

intersecting D6, D2, S5A, <strong>and</strong> W in the configuration<br />

0 1 2 3 4 5 6 7 8 9<br />

D6 + + +++++−−−<br />

S5 + + ++++∼−−−<br />

D2 + + ∼∼∼−+−−−<br />

W + →∼∼∼∼∼−−−<br />

(20.36)<br />

was proposed in order to describe d = 4 BHs. In the extreme limit (which had been constructed<br />

before in [606, 680]) it has a regular horizon <strong>and</strong> moduli that are regular there (if<br />

the D2 were placed in directions 012, then the moduli would be singular at the horizon).<br />

The construction of the d = 10 solution is similar to that of the solution associated with the<br />

d = 5BHwhich we have discussed in detail <strong>and</strong> we will therefore omit unnecessary details<br />

here.<br />

The black intersecting solution is<br />

d ˆs 2 s = H − 1 2<br />

D6 H − 1 <br />

2<br />

D2 H −1<br />

W Wdt2 <br />

1 − HW dy + αW(H −1<br />

<br />

W − 1)dt2<br />

− H − 1 2<br />

D6 H 1 2<br />

D2 [(dy2 ) 2 + (dy 3 ) 2 + (dy 4 ) 2 + (dy 5 ) 2 ]<br />

− H − 1 2<br />

D6 H − 1 2<br />

D2 HS5(dy 6 ) 2 − H 1 2<br />

D6 H 1 2<br />

D2 HS5[W −1 dr 2 + r 2 d 2 (2) ],<br />

e−2 ˆφ −2 ˆφ0 = e H 3 2<br />

D6H − 1 2<br />

D2<br />

Ĉ (3) ty 1 y 6 = αD2e − ˆφ0<br />

Hi = 1 + ri<br />

r , α2 i<br />

H −1<br />

S5 ,<br />

ˆB (6) ty 1 ···y 5 = αS5e −2 ˆφ0<br />

H −1<br />

D2 − 1 , Ĉ (7) ty 1 ···y 6 = αD6e − ˆφ0<br />

−1<br />

HS5 − 1 ,<br />

−1<br />

HD6 − 1 ,<br />

=+1, i = D6, D2, S5, W,<br />

W = 1 + ω<br />

r , ω= ri(1 − α2 i ), i = D6, D2, S5, W,<br />

(20.37)<br />

We dimensionally reduce this solution in three steps: first on S 1 (y 1 ), then on T 4

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