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Gravity and Strings

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where dρ 2 + ρ 2 d 2 (2)<br />

7.1 Schwarzschild’s solution 199<br />

≡ d x 2<br />

3<br />

<strong>and</strong> ρ =|x3|.<br />

16. Yet another system of coordinates: let us consider some arbitrary coordinate system<br />

{y α } <strong>and</strong> let us take four scalar functions labeled by µ = 0, 1, 2, 3ofthe coordinates<br />

y α <strong>and</strong> H µ (y), which we require to be harmonic<br />

∇ 2 H µ = 1<br />

<br />

αβ<br />

√ ∂α |g| g ∂β H<br />

|g| µ<br />

= 0. (7.27)<br />

Now we can define new coordinates x µ ≡ H µ (y), which are called harmonic coordinates.Inthe<br />

system of harmonic coordinates, the above equation takes the form of<br />

a condition on the metric:<br />

∂α<br />

|g| g αµ <br />

= 0. (7.28)<br />

If we exp<strong>and</strong> the metric in a perturbation series around flat spacetime,<br />

gµν = ηµν + χh (0) µν + χ 2 h (1) µν + ···,<br />

g µν = η µν − χh (0)µν + χ 2 h (0)µρ h (0) ρ ν − h (1)µν ,<br />

g = 1 + χh (0) + χ 2 h (1) + 1<br />

(0) 2 (0)µν (0)<br />

h − h h 2<br />

µν ,<br />

<br />

1<br />

|g| =1 + 2χh(0) + 1<br />

4χ 2 2h (1) + h (0) 2 − 2h (0)µν h (0) <br />

µν ,<br />

<br />

µν µν<br />

|g| g = η − χ ¯h (0)µν + χ 2 −h (1) µνh (0)µρ h (0) ρ ν − h (0) h (0)µν<br />

+ 1<br />

(1) (0) 2 (0)αβ (0) µν<br />

2h + h − 2h h 4<br />

αβ η ,<br />

(7.29)<br />

where, as usual, h ≡ hρ ρ <strong>and</strong> ¯h (0) µν ≡ h (0) µν − 1<br />

2ηµνh (0) .Onsubstituting these into<br />

the above equation, we find that the linear perturbation h (0) µν of the metric in<br />

harmonic coordinates is in the harmonic gauge, Eq. (3.57), but the next order is<br />

not.<br />

To set the Schwarzschild solution in a harmonic coordinate system it turns out that<br />

we just have to shift the Schwarzschild radial coordinate r ≡ rh − ω/2 toobtain<br />

ds 2 =<br />

<br />

rh + ω/2<br />

(dct)<br />

rh − ω/2<br />

2 −<br />

<br />

rh − ω/2<br />

dr<br />

rh + ω/2<br />

2 h + (rh − ω/2) 2 d 2 (2) , (7.30)<br />

<strong>and</strong> reexpress the metric in terms of coordinates x3 (having nothing to do with the<br />

isotropic coordinates introduced before) such that rh =|x3| using rhdrh =x3 · d x3

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