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Gravity and Strings

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232 The Reissner–Nordström black hole<br />

(c) The relative values of their charge <strong>and</strong> mass are such that, if we have two of<br />

them, M1 = 2|q1| <strong>and</strong> M2 = 2|q2|,itwill always happen that<br />

G (4)<br />

N M1M2 = 4G (4)<br />

N |q1q2|, (8.80)<br />

<strong>and</strong>, if both charges have the same sign <strong>and</strong> we divide by the relative distance<br />

between them, we obtain<br />

F12 =−G (4) M1M2<br />

N<br />

r 2 12<br />

+ 4G (4) q1q2<br />

N<br />

r 2 = 0. (8.81)<br />

12<br />

This is nothing but the force between two point-like, massive, charged,<br />

non-relativistic objects on account of Eqs. (3.140) <strong>and</strong> (8.61) <strong>and</strong> it vanishes,<br />

so they will be in equilibrium. Then, this suggests that it should be possible to<br />

find static solutions describing two (or many) ERN BHs in equilibrium.<br />

(d) On shifting the radial coordinate r = ρ + G (4)<br />

N M of the ERN metric, it becomes<br />

ds 2 <br />

= 1 + G(4)<br />

N M<br />

ρ<br />

−2<br />

dt 2 −<br />

<br />

1 + G(4)<br />

N M<br />

ρ<br />

2 dρ 2 2 2<br />

+ ρ d(2) . (8.82)<br />

On defining new Cartesian coordinates x3 = (x 1 , x 2 , x 3 ) such that |x3|=ρ <strong>and</strong><br />

d x 2<br />

3 = dρ2 + ρ2d 2 (2) ,weobtain a new form of the ERN solution:<br />

ds 2 = H −2 dt 2 − H 2 d x 2<br />

3 ,<br />

Aµ =−2δµt sign(q) H −1 − 1 ,<br />

H = 1 + 2G(4)<br />

N |q|<br />

|x3|<br />

N M<br />

G(4)<br />

= 1 +<br />

|x3|<br />

.<br />

(8.83)<br />

Observe that, in this case, due to the shift in the radial coordinate, the event<br />

horizon is placed at x3 = 0, which in flat Minkowski spacetime is just a point.<br />

It is, though, easy to see that the surface labeled by x3 = 0 isnot just a point<br />

but isasphere of finite area because in the limit ρ → 0 one has to take into<br />

account the ρ 2 factor of d 2 (2) that cancels out the poles in H 2 ,sothe induced<br />

metric in the ρ = 0, t = constant hypersurface is, indeed,<br />

ds 2 =−(G (4)<br />

N M)2d 2 (2) . (8.84)<br />

H is a harmonic function in the three-dimensional Euclidean space spanned<br />

by the coordinates x3, i.e. it satisfies<br />

∂i∂i H = 0. (8.85)<br />

This fact could just be a coincidence but, if we use Eq. (8.83) as an Ansatz<br />

in the equations of motion without imposing any particular form for H, we

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